Well, it really depends on the context they are in. For instance,

is different than

or

or

They all are interpret differently. For instance, one is a line, another is a square and one is a cube.
5 - 7 = - 2 ;
- 2 - 7 = - 9 ;
-9 - 7 = -16 ;
"common difference" d is - 7 ;
The n-th term of an arithmetic sequence is of the form <span>an = a1 + (n – 1)d ;
</span>a50 = 5 + 49 × ( - 7 ) = 5 - 343 = - 338;
Answer:
I'm assuming (4,2) since its not gathered with the other points
9514 1404 393
Answer:
AB = 10
BC ≈ 11.40
Step-by-step explanation:
The distance formula is useful for finding distances between points.
d = √((x2 -x1)² +(y2 -y1)²)
AB = √((18 -10)² +(4 -10)²) = √(8² +(-6)²) = √100
AB = 10
__
BC = √((25 -18)² +(-5-4)²) = √(7² +(-9)²) = √130
BC ≈ 11.40
_____
A sketch tool can be useful for finding or checking the answer.
Answer:
<em>The building is 61.5 m tall</em>
Step-by-step explanation:
The image below is a diagram where all the given distances and angles are shown. We have additionally added some variables:
h = height of the building
a, b = internal angles of each triangle
x = base of each triangle
The angles a and b can be easily found by subtracting the given angles from 90° since they are complementary angles, thus:
a = 90° - 37° = 53°
b = 90° - 42° = 48°
Now we apply the tangent ratio on both triangles separately:



From the last equation:

Substituting into the first equation:

Operating on the right side:

Rearranging:

Solving for h:

Calculating:
h = 61.5 m
The building is 61.5 m tall