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victus00 [196]
3 years ago
15

Please help asap !!!!!! what vaule of x makes the equation true 3(x-4)=15

Mathematics
1 answer:
DaniilM [7]3 years ago
5 0

3(x-4) = 15

Distribute the 3:

3x-12 = 15

Add 12 to both sides:

3x = 27

Divide both sides by 3:

X = 9

The answer is D. 9

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A carpenter can do a job in two hours. His assistant can do the same job in three hours. How long would it take them to do the j
OlgaM077 [116]

The carpenter makes 1/4 of the job per hour.

The assistant makes 1/6 of the job per hour.

When they work together, they make 1/4 + 1/6 = 6/24 + 4/24 = 10/24 = 5/12 of the job each hour.

Thus, it will take 12/5 = 2 2/5 hours = 2 hours and 24 minuets for them to finish the job working together.

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Find the GCF. 14abc and 28 a 2 b 2 c 3
9966 [12]
4 because 14abc would equal 108 the factors of 108 are 1,2,3,4,6,9,12,18,27,36,54,108 the factors of 28 are 1,2,4,7,14,28 so it's 4
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3 years ago
Are the expressions below<br> equivalent?<br> 3(4x + 8)<br> 12x + 24
pantera1 [17]

Answer:

they are both equal 12x+8 is equal to 12x+24

Step-by-step explanation:

distribute:

3 x 4x = 12x      3 x 4 = 24

3 0
3 years ago
Human visual inspection of solder joints on printed circuit boards can be very subjective. Part of the problem stems from the nu
olga_2 [115]

Answer:

a

The probability that the selected joint was judged to be defective by neither of the two inspectors is   P(A' n B' ) = 0.8855

b

The probability that the selected joint was judged to be defective by inspector B but not by inspector A  is  P(A' n B) =0.0403

Step-by-step explanation:

From the question we are told that

   The sample size is n_s =  10000

    The number of outcome for inspector A is  n__{A}} = 742

    The number of outcome for inspector B is  n__{B}} = 745

     The number of joints judged defective by both inspector is n(A u B) =  1145

The the probability that the selected joint was judged to be defective by neither of the two inspectors is mathematically represented as

      P(A' n B' ) =  1 - P(A u B)

Now

       P(A\ u \ B) = \frac{n(Au B)}{n_s }

substituting values

        P(A\ u \ B) = \frac{1145}{ 10 000 }

So  

      P(A' n B' ) =  1 - \frac{1145}{10 000}

     P(A' n B' ) = 0.8855

the probability that the selected joint was judged to be defective by inspector B but not by inspector A  is mathematically represented as

     P(A' n B) =  P(A \ u \ B) -P(A)

Now

        P(A) =  \frac{n__{A}}{n_s}

substituting values

       P(A) =  \frac{742}{10 000}

So

     P(A' n B) =   \frac{1145}{10 000}  - \frac{742}{10 000}

    P(A' n B) =0.0403

7 0
3 years ago
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