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leonid [27]
3 years ago
6

Solving quadratics equations by square root method

Mathematics
2 answers:
Zielflug [23.3K]3 years ago
7 0
Can you elaborate? are you
looking for an overall explanation or asking for a specific questions
Luba_88 [7]3 years ago
7 0

Answer:

Step-by-step explanation:

Here is an example:

3x^{2} +7=55

-7 on both sides of the equation

3x^{2} =48

divide by 3 on both sides

x^{2} =16

square root the x^{2} and 16

x=±4

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What are 4 ways you can write 3 times x?
alina1380 [7]
1) 3<em>x</em>
2) 3<em>(x)</em>
3) 3·<em>x</em>
4) 3*<em>x</em>
5 0
4 years ago
Read 2 more answers
Can anyone please help
Olenka [21]
Hello,

9)
∠DBC=90-54=36°
∠CAD=∠DBC=36°

10)
∠BOC=1/2(360-2*100)=1/2*160=80°
∠l=1/2∠AOD=1/2∠BOC=40°

11)
JL=10
JA=7==>AL=10-7=3

LC=AL=3
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CK=11-3=8

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6 0
3 years ago
At a concession stand five hotdogs and two hamburgers cost 8.00 two hotdogs and five hamburgers cost 9.50 find the cost of one h
Svetach [21]
Think of this situation as a system of equations.

let y be the price of hotdogs
let x be the price of hamburgers

5y + 2x = 8
2y + 5x = 9.50

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substitution, elimination, matrices, etc
6 0
4 years ago
Simplify $\sqrt[3]{1+8} \cdot \sqrt[3]{1+\sqrt[3]{8}}$.
Margaret [11]

Answer:

its hard to read with all the different symbols, but try yawhtam (read backwards. wont let me post the real website) , i hope this helps!

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6 0
4 years ago
Let be the set of permutations of whose first term is a prime. If we choose a permutation at random from , what is the probabili
Dennis_Churaev [7]

Answer:

Pr = \frac{1}{6}

Step-by-step explanation:

Given

S = \{1,2,3,4,5\}

n = 5

Required

Probability the third term is 3

First, we calculate the possible set.

The first must be prime (i.e. 2, 3 and 5) --- 3 numbers

2nd \to 4\ numbers

3rd \to 3\ numbers

4th \to 2\ numbers

5th \to 1\ number

So, the number of set is:

S = 3 * 4 * 3 * 2 * 1

S = 72

Next, the number of sets if the third term must be 2

1st \to 2 i.e. 1 or 5

2nd \to 3\ numbers ---- i.e. remove the already selected first term and the 3rd the compulsory third term

3rd \to 1\ number i.e. the digit 2

4th \to 2\ numbers

5th \to 1\ number

So

r = 2 * 3 * 1 * 2 * 1

r = 12

So, the probability is:

Pr = \frac{r}{S}

Pr = \frac{12}{72}

Pr = \frac{1}{6}

8 0
3 years ago
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