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3 years ago

Do objects with more mass have more friction

2 answers:

8 0

yes. object with more mass tend to have more friction. for example if you slide a heavy box across the floor, it will have more friction with the floor due to gravity.

Nikitich [7]3 years ago

6 0

Yes. An object of large mass is pulled down onto a surface with a greater force than an object of low mass and, as a consequence, there is greater friction between the surface of the heavy object than between the surface of the light object.

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A rock resting high in a cliff is an example of an object with what type of energy?

Basile [38]

<span>potential energy! Because the rock has the ability to possible move! So :)</span>

8 0

4 years ago

Read 2 more answers

A car with mass mc = 1490 kg is traveling west through an intersection at a magnitude of velocity of vc = 9.5 m/s when a truck o

icang [17]

Answer:

v= - 4.507 i - 2.363 j

Explanation:

Given that

mc= 1490 kg

vc= 9.5 m/s ( - i)

mt= 1650 kg

vt = 6.4 m/s ( -j)

There is any external force so linear momentum will remain conserve.

Lets take final speed is v.

mc .vc + mt . vt = ( mc+mt) v

1490 x 9.5 ( - i) + 1650 x 6.4 ( -j) = ( 1490+1650) v

14,155 ( -i) + 10,560 ( - j) = 3140 v

v= - 4.507 i - 2.363 j

3 0

4 years ago

A stone whirled on a string experiences a centripetal acceleration of 10 m/s². If the string were shortened to half its length (

LUCKY_DIMON [66]

Answer:

a = 80 m/s²

Explanation:

10 = v²/r

a = (2v)²/(r/2)

a = 4v²•(2/r)

a = 8(v²/r)

a = 8(10)

a = 80 m/s²

4 0

3 years ago

How can you increase the magnitude of friction between two surfaces ? How can you decrease the magnitude of friction

Mice21 [21]

The frictional force between two surfaces is given by:
$F_f = \mu F_p$
where
$\mu$ is the coefficienct of friction
$F_p$ is the force with which one surface is pushed against the other one

Looking at the formula, we see that there are two possible ways to increase the friction:
1) by increasing the coefficient of friction $\mu$ (for instance, by making the surfaces more "rough"
2) by increasing $F_p$ , the force with which one surface is pushed against the other

Similarly, in order to decrease the friction, the two possible ways are:
1) by reducing the coefficient of friction
2) by reducing the force $F_p$

8 0

4 years ago

Does the dependenceof the orbital energy on nmake sense in terms of the total number of nodes in each type of orbital?.

erma4kov [3.2K]

Answer:The 2s orbital different than the 1s orbital because the 2s orbital extends farther from the nucleus than the 1s.

As we move away from the nucleus, the values of the principal quantum number (n) continues to increase.

As the principal quantum number (n) increases, the orbital becomes farther away from the nucleus.

The higher energy orbital are always larger than the orbitals closer to the nucleus.

Hence, the 2s orbital different than the 1s orbital because the 2s orbital extends farther from the nucleus than the 1s.

Explanation:

5 0

3 years ago