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Pie
3 years ago
10

The thickest and strongest chamber in the human heart is the left ventricle, responsible during systole for pumping oxygenated b

lood through the aorta to rest of the body. Assume aortic blood starts from rest and accelerates at 22.0 m/s2 to a peak speed of 1.01 m/s.
(a) How far does the blood travel (in m) during this acceleration?

_____________ m

(b) How much time (in s) is required for the blood to reach its peak speed?

_____________s
Physics
1 answer:
Bess [88]3 years ago
4 0

Answer:

(a). The blood travel during this acceleration is 0.0231 m.

(b). The time for the blood to reach its peak speed is 0.0459 sec.

Explanation:

Given that,

Acceleration = 22.0 m/s²

Speed = 1.01 m/s

(a). We need to calculate the distance

Using equation of motion

v^2=u^2+2as

Where, v = final speed

u = initial speed

a = acceleration

s = distance

Put the value into the formula

(1.01)^2=0+2\times22.0\times s

s=\dfrac{(1.01)^2}{2\times22.0}

s=0.0231\ m

(b). We need to calculate the time

Using equation of motion

v =u+at

Put the value into the formula

1.01=0+22t

t=\dfrac{1.01}{22}

t=0.0459\ sec

Hence, (a). The blood travel during this acceleration is 0.0231 m.

(b). The time for the blood to reach its peak speed is 0.0459 sec.

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