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Alisiya [41]
3 years ago
13

How can you increase the magnitude of friction between two surfaces ? How can you decrease the magnitude of friction

Physics
1 answer:
Mice21 [21]3 years ago
8 0
The frictional force between two surfaces is given by:
F_f = \mu F_p
where
\mu is the coefficienct of friction
F_p is the force with which one surface is pushed against the other one

Looking at the formula, we see that there are two possible ways to increase the friction:
1) by increasing the coefficient of friction \mu (for instance, by making the surfaces more "rough"
2) by increasing F_p, the force  with which one surface is pushed against the other

Similarly, in order to decrease the friction, the two possible ways are:
1) by reducing the coefficient of friction
2) by reducing the force F_p
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An angry physics student releases a wrecking ball as shown. The wrecking ball is just about to hit the building at the final tim
daser333 [38]

Answer:

the force between the building and the ball is non-conservative (friction-type force)

Explanation

Explanation:For this exercise the student must create an impulse to move the ball towards the building, in this part he performs positive work since the applied force and the displacement are in the same direction.

When the ball moves it has a kinetic energy and if its height increases or decreases its potential energy also changes, but the sum of being must be equal to the initial work.

When the ball arrives and collides with the building, non-conservative forces, of various kinds; rubbing, breaking, etc. It transforms this energy into a part of heat and another in mechanical energy that the building must absorb, let us destroy its wall

Consequently, the force between the building and the ball is non-conservative (friction-type force

6 0
3 years ago
t is the estimated distance traveled through the air by a marshmallow that is launched from a 15- cm long launcher when it is pl
DerKrebs [107]

Answer:

10

Explanation:

15 cm minus 5 cm

5 0
3 years ago
A 325 N force applied to an object for 5.5 s. What’s the impulse?
vazorg [7]
According to Newton second law of motion, the resultant force is directly proportional to the rate of change in momentum while maintaining other factors constant. Therefore, F = (mv-mu)/t where F is the resultant force , m is the mass of the object, v is the final velocity and u is the initial velocity.
Hence, Ft = mv-mu, but impulse is given by force multiplied by time, thus, impulse is equivalent to the change in momentum.
Impulse = Ft
              = 325 × 2.2 sec
              = 715 Ns
4 0
3 years ago
In this example we see how thermal expansion can actually throw off the accuracy of a length-measuring device—namely, a tape mea
Ulleksa [173]

Answer:

The new length is 50.00885m

Explanation:

linear thermal expansion coefficient Fe 11.8e-6 /K

The new length can be determined using the following equation:

∆L/L = α∆T, where α is linear thermal expansion coefficient

∆L = Lα∆T = 50(11.8e-6)(35-20) = 0.00885 m

New length = ( 50.000 + 0.00885)m =

New length = 50.00885 m

5 0
3 years ago
Read 2 more answers
The near point of an eye is 48.5 cm. A corrective lens is to be used to allow this eye to focus clearly on objects at the distan
Masteriza [31]

Answer:

The focal length of the lens should be -51.5 cm (a concave lens).

Explanation:

The purpose of the lens is to make objects at 48.5 cm appear at the healthy near point. The healthy near point is 25.0 cm.

We use the lens formula

\dfrac{1}{f} = \dfrac{1}{u} + \dfrac{1}{v}

where <em>f</em> = focal length, <em>u</em> = object distance and <em>v</em> = image distance.

In this case, <em>u</em> = 48.5 cm and <em>v</em> = -25.0 cm.

<em>v</em> is negative because the image is virtual an not real. (Here, we are using the real-is-positive sign convention)

\dfrac{1}{f} = \dfrac{1}{48.5} + \dfrac{1}{-25.0} = -\dfrac{23.5}{1212.5}

f = -51.5

The negative sign indicates the lens is concave.

3 0
3 years ago
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