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3 years ago

7

A stone whirled on a string experiences a centripetal acceleration of 10 m/s². If the string were shortened to half its length (

one-half the radius) and the speed were doubled, calculate the centripetal acceleration. _____m/s2

1 answer:

LUCKY_DIMON [66]3 years ago

4 0

Answer:

a = 80 m/s²

Explanation:

10 = v²/r

a = (2v)²/(r/2)

a = 4v²•(2/r)

a = 8(v²/r)

a = 8(10)

a = 80 m/s²

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