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Archy [21]
3 years ago
7

A stone whirled on a string experiences a centripetal acceleration of 10 m/s². If the string were shortened to half its length (

one-half the radius) and the speed were doubled, calculate the centripetal acceleration. _____m/s2
Physics
1 answer:
LUCKY_DIMON [66]3 years ago
4 0

Answer:

a = 80 m/s²

Explanation:

10 = v²/r

a = (2v)²/(r/2)

a = 4v²•(2/r)

a = 8(v²/r)

a = 8(10)

a = 80 m/s²

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Answer:

B) 4500 Pa

Explanation:

As pressure is force per unit area,

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It stands to reason that the smallest pressure for a given force is when it is shared by the largest area.

The possible areas are

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0.30(0.50) = 0.15 m²

0.40(0.50) = 0.20 m²

The pressure when the face with the largest area (0.20 m²) is down is

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the other possible pressures would be

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8 0
4 years ago
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