Question

I want to use a galvanic cell to power a 60-watt light bulb. Complete the following steps to determine how long the galvanic cell will power the light bulb before running out.
a.) The galvanic cell uses the following solutions: 0.81 L 1.5 M Cr2(SO4)3 solution and 1.2 L 0.81 M Au(NO3)3 solution. Write down the balanced chemical equations of the dissolution of Cr2(SO4)3and Au(NO3)3 into ions in water.

Answer 1

Explanation:

On dissolution of chromium(II) sulfate is water 2 ions of chromium(III) ion and and 3 sulfate ions are formed.

The balanced chemical equations of the dissolution of chromium (II) sulfate:

$Cr_2(SO_4)_3(aq)\rightarrow 2Cr^{3+}(aq)+3SO_4^{2-}(aq)$

On dissolution of gold(III)nitrate is water 1 ions of gold(III) ions and and 3 ions of nitrate ions are formed.

The balanced chemical equations of the dissolution of gold(III) nitrate:

$Au(NO_3)_3(aq)\rightarrow Au^{3+}(aq)+3NO_3^{-}(aq)$