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Eduardwww [97]
4 years ago
14

For a reaction with ΔH o = 65 kJ/mol, decide if the following statement is true. If the statement is false, choose the statement

that makes it true. Select the single best answer.
The product is favored at equilibrium. (Assume the entropy term is small compared to the enthalpy term)

(A) The statement is false. The starting material is favored at equilibrium.
(B) The statement is true.
(C) The statement is false. Neither the product nor the starting material is favored at equilibrium.
(D) The statement is false. The equilibrium position of the reaction cannot be approximated
Chemistry
1 answer:
ss7ja [257]4 years ago
3 0

Answer:

(A) The statement is false. The starting material is favored at equilibrium

Explanation:

As we know that type of reaction is predicted by value Gibbs free energy.

ΔG >0 It means that reaction is non spontaneous and favors the reactant of the reaction.

ΔG <0 It means that reaction is spontaneous and favors the product of the reaction.

As we know that

ΔG = ΔH -T ΔS

Here given that Assume the entropy term is small compared to the enthalpy term so ΔS = 0

⇒ ΔG = ΔH

Given that

ΔH o = 65 kJ/mol,

ΔG = ΔH  = 65 kJ/mol

ΔG >0 It means that reaction is non spontaneous and favors the reactant of the reaction.

So the option A is correct.

(A) The statement is false. The starting material is favored at equilibrium.

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Answer:

We love the noble gases. Some scientists used to call them the inert gases. It didn't really work because there are a few other gases that are basically inert but not noble gases. Nitrogen (N2) might be considered an inert gas, but it is not a noble gas. The noble gases are another family of elements, and all of them are located in the far right column of the periodic table. For all of you budding chemists, the far right is also known as Group Zero (Group 0) or Group Eighteen (Group XVIII). This family has the happiest elements of all.

Explanation:

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8 0
3 years ago
If one mole of atoms or molecules is equal to 6.022 × 1023 atoms or molecules, how many molecules are in a 23.45 g sample of cop
antiseptic1488 [7]

The number of molecules that are needed in a 23.45 g sample of copper (ii) hydroxide, are 1.45 x 10²³.

<h3>What is Avogadro's number?</h3>

Avogadro's number is the measurement of the one mole of any substance that is equal to the Avogadro's number.

Avogadro's number is 6.022 × 10²³.

To calculate the moles

Moles = mass / molar mass

Mass is 23.45 g

Molar mass is 97.562

Putting the value in equation

Moles = 23.45 g/ 97.562 = 0.24 mol.

The moles of copper (II) hydroxide has been 0.24 mol.

The number of molecules in 0.24 mol sample has been driven by:

1 mol = 6.022 × 10²³.

0.24 mol = 0.24 x 10²³.

0.24 mol = 1.45 x 10²³.

Thus, the number of molecules that are needed in a 23.45 g sample of copper (ii) hydroxide, are 1.45 x 10²³.

Learn more about Avogadro's number

brainly.com/question/1445383

#SPJ1

5 0
2 years ago
Help needed ASAP, I will mark your answer as brainliest.
evablogger [386]

Answer:

b

Explanation:

b

4 0
3 years ago
Read 2 more answers
5.25 x 10^32 atoms of K to grams
NNADVOKAT [17]

Answer:

3.40x10¹⁰ grams

Explanation:

First we<u> convert 5.25x10³² atoms to moles</u>, using <em>Avogadro's number</em>:

5.25x10³² atoms ÷ 6.023x10²³ atoms/mol = 88.72x10⁸ mol

Then we<u> convert K moles to grams</u>, using its <em>molar mass</em>:

88.72x10⁸ mol * 39 g/mol = 3.40x10¹⁰ g

So 5.25x10³² atoms of K would weigh 3.40x10¹⁰ grams.

3 0
3 years ago
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Aleonysh [2.5K]
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