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Eduardwww [97]
4 years ago
14

For a reaction with ΔH o = 65 kJ/mol, decide if the following statement is true. If the statement is false, choose the statement

that makes it true. Select the single best answer.
The product is favored at equilibrium. (Assume the entropy term is small compared to the enthalpy term)

(A) The statement is false. The starting material is favored at equilibrium.
(B) The statement is true.
(C) The statement is false. Neither the product nor the starting material is favored at equilibrium.
(D) The statement is false. The equilibrium position of the reaction cannot be approximated
Chemistry
1 answer:
ss7ja [257]4 years ago
3 0

Answer:

(A) The statement is false. The starting material is favored at equilibrium

Explanation:

As we know that type of reaction is predicted by value Gibbs free energy.

ΔG >0 It means that reaction is non spontaneous and favors the reactant of the reaction.

ΔG <0 It means that reaction is spontaneous and favors the product of the reaction.

As we know that

ΔG = ΔH -T ΔS

Here given that Assume the entropy term is small compared to the enthalpy term so ΔS = 0

⇒ ΔG = ΔH

Given that

ΔH o = 65 kJ/mol,

ΔG = ΔH  = 65 kJ/mol

ΔG >0 It means that reaction is non spontaneous and favors the reactant of the reaction.

So the option A is correct.

(A) The statement is false. The starting material is favored at equilibrium.

You might be interested in
hydrogen and oxygen gas combine to form water. if 1.00g of hydrogen and 1.00g of oxygen are reacted, what is the theoretical yie
AlekseyPX

The equation for the reaction of hydrogen and oxygen is:

2H_2 + O_2 \rightarrow 2H_2O

M_r(H_2) = 2\\\\\therefore n(H_2) = \frac{1}{2}= 0.5mol = n(H_2O)\\\\m(H_2O) = 0.5 \times M(H_2O) = 0.5 \times 18 = 9g

Thus, the theoretical yield of water is 9 grams.

6 0
3 years ago
If 588 grams of FeS2 is allowed to react with 352 grams of O2 according to the following equation, how many grams of Fe2O3 are p
Rainbow [258]

<u>Answer:</u> The mass of iron (III) oxide  produced is 782.5 grams

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

  • <u>For </u>FeS_2<u> :</u>

Given mass of FeS_2 = 588 g

Molar mass of FeS_2 = 120 g/mol

Putting values in equation 1, we get:

\text{Moles of }FeS_2=\frac{588g}{120g/mol}=4.9mol

  • <u>For </u>O_2<u> :</u>

Given mass of O_2 = 352 g

Molar mass of O_2 = 32 g/mol

Putting values in equation 1, we get:

\text{Moles of }O_2=\frac{352g}{32g/mol}=11mol

The chemical equation for the reaction of FeS_2 and oxygen gas follows:

FeS_2+O_2\rightarrow Fe_2O_3+SO_2

By Stoichiometry of the reaction:

1 mole of FeS_2 reacts with 1 mole of oxygen gas

So, 4.9 moles of FeS_2 will react with = \frac{1}{1}\times 4.9=4.9mol of oxygen gas

As, given amount of oxygen gas is more than the required amount. So, it is considered as an excess reagent.

Thus, FeS_2 is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

1 mole of FeS_2 produces 1 mole of iron (III) oxide

So, 4.9 moles of FeS_2 will produce = \frac{1}{1}\times 4.9=4.9moles of iron (III) oxide

Now, calculating the mass of iron (III) oxide  from equation 1, we get:

Molar mass of iron (III) oxide  = 159.7 g/mol

Moles of iron (III) oxide  = 4.9 moles

Putting values in equation 1, we get:

4.9mol=\frac{\text{Mass of iron (III) oxide}}{159.7g/mol}\\\\\text{Mass of iron (III) oxide}=(4.9mol\times 159.7g/mol)=782.5g

Hence, the mass of iron (III) oxide  produced is 782.5 grams

8 0
3 years ago
In what orbital would to valence electrons of strontium be found? a.) 5s b.) 4s c.) none d.) 5p​
KonstantinChe [14]

Answer:

The correct answer is 5s

Explanation:

Strontium atomic number = 38

Electronic configuration is $1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6} 3d^{10} 4s^{2} 4p^{6} 5s^{2}

As $5s$ orbital is valence orbital in strontium, the outer electrons exists in that orbital only.

4 0
3 years ago
What is the molarity of a solution that contains 9.63 grams of HCl in 1.5 liters of solution? 1 H 1.01 Hydrogen 17 Cl 35.45 Chlo
madam [21]
Hey there !

Molar mass HCl :

HCl =1.01 + 35.45 => 36.46 g/mol

Number of moles ( solute) :

n = m / mm

n = 9.63 / 36.46

n = 0.2641 moles

Therefore :

M = moles / volume ( L )

M = 0.2641 / 1.5

=> 0.176 M


7 0
4 years ago
Consider the decomposition of water, is energy released or absorbed in this reaction? Discuss bond energy in your answer.!
Goshia [24]

Answer:

Then decomposition of water involves its breakdown into Hydrogen and Oxygen

The energy derived is absorbed which means it’s an endothermic reaction. If the energy is released to the surroundings/environment, it is termed as exothermic.

In an endothermic reactions, the reaction occurs when the bonds present in the reactants are broken and greater than the release of new bonds during products formation.

3 0
3 years ago
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