Answer:

Explanation:
Hello,
In this case, for the reaction between hydrochloric acid and sodium hydroxide, for 2.4 g of base, we can compute the neutralized grams of acid by applying the 1:1 molar ratio between them and their molar masses, 36.45 g/mol and 40 g/mol respectively as shown below by stoichiometry:

Best regards.
<span>64.94
First, write out an expression about what we know
0.6915 * 62.93 + 0.3085 * x = 63.55
Now solve for x
0.6915 * 62.93 + 0.3085 * x = 63.55
43.5161 + 0.3085 * x = 63.55
0.3085 * x = 20.03391
x = 64.93972
Rounding the answer to 2 decimal places gives x = 64.94</span>
Answer:
b) Conduction, convection, and radiation
Answer:
rA = 0.60 M/s
rC = 0.90 M/s
Explanation:
Let's consider the following reaction:
2 A+B ⇒ 3 C
The rate of each substance can be calculated like the change in its concentration divided by the change in time. Given the rate must always be positive, we add a minus sign before the reactants change in concentration.
![rA=-\frac{\Delta[A] }{\Delta t}](https://tex.z-dn.net/?f=rA%3D-%5Cfrac%7B%5CDelta%5BA%5D%20%7D%7B%5CDelta%20t%7D)
![rB=-\frac{\Delta[B] }{\Delta t}](https://tex.z-dn.net/?f=rB%3D-%5Cfrac%7B%5CDelta%5BB%5D%20%7D%7B%5CDelta%20t%7D)
![rC=\frac{\Delta[C] }{\Delta t}](https://tex.z-dn.net/?f=rC%3D%5Cfrac%7B%5CDelta%5BC%5D%20%7D%7B%5CDelta%20t%7D)
The rate of the reaction is equal to the rate of each substance divided by its stoichiometric coefficient.

The rate of disappearance of B is 0.30 M/s.
The rate of disappearance of A is:

The rate of appearance of C is:
