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fredd [130]
3 years ago
5

Determine the volume of a 75-gram sample of gold at stp

Chemistry
1 answer:
Anuta_ua [19.1K]3 years ago
7 0
Let V = the volume of the sample at STP.

The mass is  m = 75 g
The density of gold is 19.32 g/cm³

Because density = mass/volume, therefore
(19.32 g/cm³) = (75 g)/(V cm³)
V = (75 g)/(19.32 g/cm³) = 3.882 cm³

Answer: 3.882 cm³
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A 6 kg rock is sitting at the edge of a 100 m tall cliff. What is the potential energy of the rock with respect to the ground?
Hatshy [7]
Potential energy can be calculated by the formula Pe=mgh. Plug in your values:

Pe=mgh
Pe=(6 kg)(9.8m/s^2)(100 m)
Pe=5880 kg x m^2/s^2, or 5880 Joules
5 0
3 years ago
A teardrop-shaped hill that points the direction a glacier has flowed is a:
mote1985 [20]
The answer is A Drumlin

3 0
3 years ago
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A train travels at a speed of 30 miles per hour. If 1 mile = 1.6 kilometers, how fast is the train traveling in kilometers per m
Alina [70]
The answer 
 the speed of <span>the train traveling in kilometers per minute can be found by using the following method:
v = </span><span>30 miles per hour
</span><span>1 mile = 1.6 kilometers

just do the calculus by changing miles to kilometers
 </span>1 mile = 1.6 kilometers, so 30 miles= 1.6 km x 30 = 48 km
 so the speed of the train is
v=30 miles / hour = 48km / h = 48km / 60 mn  = 0.8 km/ mn
the answer is
<span>C- 0.8 km/min</span> 
7 0
3 years ago
Natural gas is almost entirely methane. A container with a volume of 2.65L holds 0.120mol of methane. What will the volume be if
mrs_skeptik [129]

The final volume of the methane gas in the container is 6.67 L.

The given parameters;

  • <em>initial volume of gas in the container, V₁ = 2.65 L</em>
  • <em>initial number of moles of gas, n₁ = 0.12 mol</em>
  • <em>additional concentration, n = 0.182 mol</em>

The total number of moles of gas in the container is calculated as follows;

n_t = 0.12 + 0.182 = 0.302 \ mol

The final volume of gas in the container is calculated as follows;

PV = nRT\\\\\frac{V}{n} = \frac{RT}{P} \\\\\frac{V_1}{n_1} = \frac{V_2}{n_2} \\\\V_2 = \frac{V_1 n_2}{n_1} \\\\V_2 = \frac{2.65 \times 0.302}{0.12} \\\\V_2 = 6.67 \ L

Thus, the final volume of the methane gas in the container is 6.67 L.

Learn more here:brainly.com/question/21912477

5 0
3 years ago
The conversion of cyclopropane to propene in the gas phase is a first-order reaction with a rate constant of 6.7 x 10-4 s -1 at
denpristay [2]

Answer:

C_f=0.1755M

Explanation:

Hello,

Based on the information and the units of the given data, the integrated rate law turns out into:

\frac{dC}{dt}=-kC\\ C_f=C_0exp(-kt)\\C_f=0.25M*exp(-6.7x10^{-4}s^{-1}*8.8min*\frac{60s}{1min} )\\C_f=0.1755M

Best regards.

8 0
3 years ago
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