I searched for complete question (as your question is missing with structure) and found the structure of compound attached below.
Answer: The compound can
neither act as a Hydrogen Bond Donor
nor act as a Hydrogen Bond Acceptor.
Explanation: For two compounds to build Hydrogen Bond Interactions it is compulsory that they must contain Hydrogen atoms which are directly attached to most electronegative atoms like
Fluorine,
Oxygen and
Nitrogen.
As the given compound is
2-Butene (a non polar hydrocarbon), it lacks partial positive Hydrogen (which can act as Hydrogen Bond Donor) and a most electronegative element (F, O or N) which can act as Hydrogen Bond Acceptor. Therefore, this compound will not generate any Hydrogen Bonding with water molecules and will remain immiscible in it.
Find your answer in the explanation below.
Explanation:
PV = nRT is called the ideal gas equation and its a combination of 3 laws; Charles' law, Boyle's law and Avogadro's law.
According to Boyle's law, at constant temperature, the volume of a gas is inversely proportional to the pressure. i.e V = 1/P
From, Charles' law, we have that volume is directly proportional to the absolute temperature of the gas at constant pressure. i.e V = T
Avogadro's law finally states that equal volume of all gases at the same temperature and pressure contain the same number of molecules. i.e V = n
Combining the 3 Laws together i.e equating volume in all 3 laws, we have
V = nT/P,
V = constant nT/P
(constant = general gas constant = R)
V = RnT/P
by bringing P to the LHS, we have,
PV = nRT.
Q.E.D
<span>Phosphorus trifluoride (formula PF3), is a colorless and odorless gas. is similar to carbon monoxide and this is very toxic according to my research. hope this helps.</span>
Not all matter in the reactant goes to the product. Some matter is byproducts.
At 1.0 mol/min my teacher told me when I asked her yuh