Answer: -
0.1 ml of bleach should be added to each liter of test solution.
Explanation:-
Let the volume of bleach to be added is B ml.
Density of stock solution = 1.0 g/ml
Mass of stock solution = Volume of stock x density of stock
= B ml x 1.0 g/ml
= B g
Amount of NaOCl in this stock solution = 5% of B g
= x B g
= 0.05 B g
Now each test solution must be added 5 mg/l NaOCl.
Thus each liter of test solution must have 5 mg.
Thus 0.05 B g = 5 mg
= 0.005 g
B =
= 0.1
Thus 0.1 ml of bleach should be added to each liter of test solution.
Answer:
Explanation:
To write the chemical symbol for an atom or cation with 22 electrons, we must understand some few things about an atom.
An atom is made up of positively charged paticles called protons which are located in the nucleus. The neutrons do not have any charges and are they reside together in the nucleus with the protons.
Electrons are negatively charged particles which orbits the nucleus.
Titanium in its neutral state is the 22nd element on the periodic table and it has 22 electrons.
Vanadium is the the 23rd element on the periodic table. If it loses an electron, it becomes positively charged and it is a cation.
Chromium is the 24th element on the periodic table. A loss of two electrons makes the net electrons remaining on it 22.
The symbols are:
₂₂Ti
₂₃V¹⁺
₂₄Cr²⁺
It would be 0.341 because if you add 0.229 and 0.112 it will be 0.341
6.28×1013+7.30×1011 this =13741.94
Answer:
add x to 7 and divide by 3
Explanation:
easier formula