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ollegr [7]
3 years ago
13

The coordinates of the vertices of ANGLE PQR are P(-3,3), Q(2,3), and R(-3,-4). Find the side lengths to the nearest hundredth a

nd the angle measures to the nearest degree.
Mathematics
1 answer:
Marat540 [252]3 years ago
7 0
<span>
Answer: PQ=5, QR=radical 61= 7.81, angle: 50degrees,</span>Why:PQ=|-3|+2=5PR=6<span>angle Alfa, so there is right angle triangle PQR so I can use following formula:</span>PQ^2 + RP^2=QR^2;25 + 36=QR^2;QR=radical 61<span>also I can use: sinus (angle)=PR/QR;</span><span>sin(angle)=6/radical61=0.76822 which gives angle to be little bit more than 50 degrees{sinus 50 degrees=<span>0,7660</span>}. </span>
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