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3 years ago

Elizabeth attempts a field goal by kicking a football from the ground with an initial vertical

Mathematics

1 answer:

sammy [17]3 years ago

5 0

$\bf ~~~~~~\textit{initial velocity} \\\\ \begin{array}{llll} ~~~~~~\textit{in feet} \\\\ h(t) = -16t^2+v_ot+h_o \end{array} \quad \begin{cases} v_o=\stackrel{64}{\textit{initial velocity of the object}}\\\\ h_o=\stackrel{0\qquad \textit{from the ground}}{\textit{initial height of the object}}\\\\ h=\stackrel{}{\textit{height of the object at "t" seconds}} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}$

$\bf h(t)=-16t^2+64t+0\implies h(t)=-16t^2+64t\implies \stackrel{\textit{hits the ground}~\hfill }{0=-16t^2+64t} \\\\\\ 0=-16t(t-4)\implies t= \begin{cases} 0\\ \boxed{4} \end{cases}$

Check the picture below, it hits the ground at 0 feet, where it came from, the ground, and when it came back down.

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9% percent are in the band. the band has 180 members.how many people are in school

dimulka [17.4K]

9% of n is 180
0.09n=180
n=2000

4 0

2 years ago

Problem 2-11 (Algorithmic) Let A be an event that a person's primary method of transportation to and from work is an automobile

dangina [55]

The events are mutually exclusive, because your primary method can't be both a driving a car or taking a bus.

Since they are exclusive, the probability of the "or" clause is the sum of the probabilities:

$P(A\lor B)=P(A)+P(B)=0.48+0.32=0.8$

Since a person primarily takes a bus with probability 0.32, the opposite happens with probability

$1-P(B) = 1-0.32=0.68$

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3 years ago

F+4/g=6 Solve for F

Svet_ta [14]

$\dfrac{f+4}{g}=6\ \ \ \ |multiply\ both\ sides\ by\ g\\\\f+4=6g\ \ \ \ |subtract\ 4\ from\ both\ sides\\\\\boxed{f=6g-4}$

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3 years ago

Write an equation that models this situation.

Nimfa-mama [501]

Answer:

Step-by-step explanation:

the ideal way to put the equation would be x= 6 x 8 but since that is not an option B is the answer. the keyword is "each" that allows you to know that you will be multiplying those to numbers.

so the only one that allows you to multiply 6 and 8 is B when you multiply 6 to the other side.

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2 years ago

Travel time data is collected on an arterial. With 30 runs, an average travel time of 152 seconds is computed over the 2.0 miles

o-na [289]

Answer:

The 95% confidence bounds is $145.80 < \mu < 158.19$

It was not necessary to make any assumption about the shape of the travel time distribution

Step-by-step explanation:

From the question we are told that

The sample size is n = 30

The sample mean is $\=x = 152$

The standard deviation is $\sigma = 17.3 \ second$

From the question we are told the confidence level is 95% , hence the level of significance is

$\alpha = (100 - 95 ) \%$

=> $\alpha = 0.05$

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{\sigma }{\sqrt{n} }$

=> $E = 1.96 * \frac{17.3 }{\sqrt{30} }$

=> $E = 6.19$

Generally 95% confidence bounds is mathematically represented as

$\= x -E < \mu < \=x +E$

=> $152 -6.19 < \mu < 152 -6.19$

=> $145.80 < \mu < 158.19$

This 95% confidence bounds show that there is 95% confidence that the true mean lies within this bound hence there is it was not necessary to make any assumption about the shape of the travel time distribution

5 0

2 years ago