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Marianna [84]
3 years ago
8

If you could be anything in the world what would it be

Mathematics
2 answers:
shusha [124]3 years ago
5 0

I would be a pine cone cause it was an option                                                                                          

slava [35]3 years ago
4 0

Not mathematics, but if I could be anything in the world, I'd be a bird.

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6squated - 3 squared
weeeeeb [17]

Answer:

27 is the answer to this equation

Step-by-step explanation:

6 times 6 equals 36

3times 3 equals 9

36

-9

27

7 0
2 years ago
Use the law of wines to find the value of y. Round to the nearest Tenth
Eva8 [605]

Answer:

y ≈ 2.5

Step-by-step explanation:

Using the Sine rule in Δ XYZ

\frac{sinZ}{XY} = \frac{sinY}{XZ} , substitute values

\frac{sin50}{2} = \frac{sin75}{y} ( cross- multiply )

y sin50° = 2 sin75° ( divide both sides by sin50° )

y = \frac{2sin75}{sin50} ≈ 2.5 ( to the nearest tenth )

4 0
2 years ago
Also need help on this
Ira Lisetskai [31]
Answer is 0.5
-2 divided by -4 equals 0.5
and same thing for the rest of the equation.
8 0
3 years ago
Read 2 more answers
the length of a rectagle is 5 in longer than its width. if the perimeter of the rectangle is 58 in, find its length and width
dolphi86 [110]

Answer:

  • Length = 17 inches

  • Width = 12 inches

⠀

Step-by-step explanation:

⠀

As it is given that, the length of a rectangle is 5 in longer than its width and the perimeter of the rectangle is 58 in and we are to find the length and width of the rectangle. So,

⠀

Let us assume the width of the rectangle as x inches and therefore, the length will be (x + 5) inches .

⠀

Now, <u>According to the Question :</u>

⠀

{\longrightarrow \qquad { \pmb{\frak {2 ( Length + Breadth )= Perimeter_{(Rectangle)} }}}}

⠀

{\longrightarrow \qquad { {\sf{2 ( x + 5 + x )= 58 }}}}

⠀

{\longrightarrow \qquad { {\sf{2 ( 2x + 5  )= 58 }}}}

⠀

{\longrightarrow \qquad { {\sf{ 4x + 10= 58 }}}}

⠀

{\longrightarrow \qquad { {\sf{ 4x = 58  - 10}}}}

⠀

{\longrightarrow \qquad { {\sf{ 4x = 48}}}}

⠀

{\longrightarrow \qquad { {\sf{ x =  \dfrac{48}{4} }}}}

⠀

{\longrightarrow \qquad{ \underline{ \boxed { \pmb{\mathfrak {x = 12}} }}} }\:  \:  \bigstar

⠀

Therefore,

  • The width of the rectangle is 12 inches .

⠀

Now, We are to find the length of the rectangle:

{\longrightarrow \qquad{ { \frak{\pmb{Length = x + 5 }}}}}

⠀

{\longrightarrow \qquad{ { \frak{\pmb{Length = 12 + 5 }}}}}

⠀

{\longrightarrow \qquad{ { \frak{\pmb{Length = 17}}}}}

⠀

Therefore,

  • The length of the rectangle is 17 inches .

⠀

8 0
1 year ago
Read 2 more answers
mark is drawing a map of his favorite park. the park is 3 miles long and 1.5 miles wide. the map scale is 1 inch = .25 miles. ho
Brilliant_brown [7]

Answer: 6 inches

Step-by-step explanation:

1.5 miles wide * 1 inch / 0.25 miles = 6 inches :D

7 0
2 years ago
Read 2 more answers
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