I need help graphing 2x-5y=5

Mr. Saba owns two food trucks. He rents two spots at the state fair. This table shows the number of tacos the two food trucks so

Nadya [2.5K]

Using the data for each truck lets calculate,

median for truck 1 - 511.5
median for truck 2 - 650.5

lets consider each statement
A.medians for both trucks are the same - wrong
median for 1 and 2 are 511.5 and 650.5 respectively

B. the two trucks sold most number of tacos on 3rd day
truck 1 sold 437 on day 3 but highest number it sold was 721 on day 1
truck 2 sold 426 on day 3 but highest number was 732 on day 6
therefore this statement too is wrong

C.
truck 1 - range between maximum(721) and minimum(425) = 296
truck 2 - maximum (732) and minimum (426) difference = 306
the range between maximum and minimum in truck 2 is 306 thats greater than range between maximum and minimum in truck 1, that's 296
therefore this statement is correct

D.
total number of tacos for each truck -
truck 1 - 5291
truck 2 - 6107
food truck 1 sold less than truck 2 therefore this statement too is wrong

5 0

2 years ago

Read 2 more answers

Y = (x)^(1/9)*Find f(x) when x=(1/2)Round your answer to the nearest thousandth.

Verizon [17]

We are given a function f ( x ) defined as follows:

$y=f(x)=x^{\frac{1}{9}}$

We are to determine the value of f ( x ) when,

$\times\text{ = }\frac{1}{2}$

In such cases, we plug in/substitue the given value of x into the expressed function f ( x ) as follows:

$y\text{ = f ( }\frac{1}{2}\text{ ) = (}\frac{1}{2})^{\frac{1}{9}}$

We will apply the power on both numerator and denominator as follows:

$f(\frac{1}{2})=\frac{1^{\frac{1}{9}}}{2^{\frac{1}{9}}}\text{ = }\frac{1}{2^{\frac{1}{9}}}$

Now we evaluate ( 2 ) raised to the power of ( 1 / 9 ).

$f\text{ ( }\frac{1}{2}\text{ ) = }\frac{1}{1.08005}$

Next apply the division operation as follows:

$f\text{ ( }\frac{1}{2})\text{ = }0.92587$

Once, we have evaluated the answer in decimal form ( 5 decimal places ). We will round off the answer to nearest thousandths.

Rounding off to nearest thousandth means we consider the thousandth decimal place ( 3rd ). Then we have the choice of either truncating the decimal places ( 4th and onwards ). The truncation only occurs when (4th decimal place) is < 5.

However, since the (4th decimal place) = 8 > 5. Then we add ( 1 ) to the 3rd decimal place and truncate the rest of the decimal places i.e ( 4th and onwards ).

The answer to f ( 1 / 2 ) to the nearest thousandth would be: