Unless you're given the value of the variables, you can't really solve for anything. The only thing you can do is simplify.
<span>39+5h+4g-2h
The only like terms are 5h and -2h.
39 + 3h + 4g
This would be the simplified version.</span>
Answer: $9
Step-by-step explanation:
Let the cost for adults be a
Let the cost for students be b.
The first van transported 2 adults and 5 students and cost $77. This will be:
2a + 5b = $77
The second van transported 2 adults and 7 students and cost $95. This will be:
2a + 7b = $95
2a + 5b = 77 ...... equation i
2a + 7b = 95 ........ equation ii
Subtract equation ii from I
-2b = -18
b = 18/2
b = $9
An student cost $9
Put the value of b into equation i
2a + 5b = 77
2a + 5(9) = 77
2a + 45 = 77
2a = 77 - 45
2a = 32
a = 32/2
a = 16
An adult costs $16
<span>(x-2/3)+(1/60)=(5/6)
x-2/3= 5/6 - 1/60
x-2/3 = 49/60
x - 2 = 49/20
x = 49/20 + 2
x = 89/20
The answer is: x = 89/20 or x = 4.45.
</span>
Answer:
I think it's {3, 6, 12, 18}
Step-by-step explanation:
Domain: all x-values that are to be used (independent values).
Answer:
21.68 minutes ≈ 21.7 minutes
Step-by-step explanation:
Given:
Initial temperature
T = 100°C
Final temperature = 60°C
Temperature after (t = 3 minutes) = 90°C
Now,
using the given equation
at T = 90°C and t = 3 minutes
or
taking the natural log both sides, we get
3k = 
or
3k = -0.2876
or
k = -0.09589
Therefore,
substituting k in 1 for time at temperature, T = 65°C
or
or
or
taking the natural log both the sides, we get
( -0.09589)t = ln(0.125)
or
( -0.09589)t = -2.0794
or
t = 21.68 minutes ≈ 21.7 minutes
