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2 years ago

How do i solve 12+4x=30+12

Mathematics

1 answer:

Elza [17]2 years ago

4 0

Answer:

x = 15/2

Step-by-step explanation:

Solve for x:

4 x + 12 = 42

Subtract 12 from both sides:

4 x + (12 - 12) = 42 - 12

12 - 12 = 0:

4 x = 42 - 12

42 - 12 = 30:

4 x = 30

Divide both sides of 4 x = 30 by 4:

(4 x)/4 = 30/4

4/4 = 1:

x = 30/4

The gcd of 30 and 4 is 2, so 30/4 = (2×15)/(2×2) = 2/2×15/2 = 15/2:

Answer: x = 15/2

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2 years ago

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The missing value is 12 in a system of equations with infinitely many solutions conditions.

It is given that in the system of equations there are two equations given:

$\rm y =n -2x+4\\\rm and \\\rm 6x+3y= ?$

It is required to find the missing value in the second equation.

<h3>What is a linear equation?</h3>

It is defined as the relation between two variables if we plot the graph of the linear equation we will get a straight line.

We have equations:

$\rm y = -2x+4 ....(1)\\ \\\rm 6x+3y= ? ....(2)$

Let's suppose the missing value is 'Z'

We know that the two pairs of equations have infinitely many solutions if and if they have the same coefficients of variables and the same constant on both sides.

From equation (1)

$\rm y = -2x+4 \\\\\rm 2x+y=4$ (multiply both the sides by 3)