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3 years ago

How do i solve 12+4x=30+12

Mathematics

1 answer:

Elza [17]3 years ago

4 0

Answer:

x = 15/2

Step-by-step explanation:

Solve for x:

4 x + 12 = 42

Subtract 12 from both sides:

4 x + (12 - 12) = 42 - 12

12 - 12 = 0:

4 x = 42 - 12

42 - 12 = 30:

4 x = 30

Divide both sides of 4 x = 30 by 4:

(4 x)/4 = 30/4

4/4 = 1:

x = 30/4

The gcd of 30 and 4 is 2, so 30/4 = (2×15)/(2×2) = 2/2×15/2 = 15/2:

Answer: x = 15/2

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3 years ago

NEED HELP WORTH 100 POINTS SHOW YOUR WORK PLEASE

tia_tia [17]

Answer:

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Q2:

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$\sqrt{15n^2}\sqrt{10n^3}$

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5 0

3 years ago

Thirty Mercedes and Audi participated in a 30 mile race. The average driving speed of the Mercedes and Audi were recorded. A ran

vladimir1956 [14]

Answer:

Median for sample 1 = 142

Median for sample 2 = 134

Step-by-step explanation:

For Sample 1:

For finding median, the data is first arranged into ascending or descending order. We are arranging the data in ascending order.

120, 130, 132, 136, 139, 142, 142, 144, 156, 165, 167

The formula for calculating the term which will be median is:

Median= ((n+1)/2)

Here in sample 1, n=11

So, putting n=11 in the formula

= ((11+1)/2)

= (12/2)

=6th term

The sixth term is 142, so

Median of sample 1=142

For Sample 2:

For finding median, the data is first arranged into ascending or descending order. We are arranging the data in ascending order.

112, 112, 113, 114, 125, 134, 141, 145, 146, 163, 165

The formula for calculating the term which will be median is:

Median= ((n+1)/2)

Here in sample 2, n=11

So, putting n=11 in the formula

=((11+1)/2)

=(12/2)

=6th term

The sixth term is 134, so

Median of sample 2=134

7 0

3 years ago

The GCF of 18 and 30 is ____.

hammer [34]

The GCF of 18 and 30 is 6

4 0

3 years ago

Read 2 more answers

how many kilograms of pure water is to be added to 100 kilograms of a 30% saline solution to make it a 10% saline solution

Irina-Kira [14]

Answer:

200 kg

Step-by-step explanation:

If w is the amount of water added, then the concentration of the solution is ...

salt/solute = 100(0.30)/(100 +w) = 0.10

30 = 10 +0.10w . . . . . simplify

20 = 0.10w . . . . . . . . subtract 10

20/0.10 = w = 200 . . . . divide by 0.10

200 kg of water must be added to dilute the solution to 10%.

4 0

3 years ago