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jasenka [17]
3 years ago
5

The radius of a circular sign is 12 12 inches. Equal parts of the sign are painted red red and yellow yellow. How many square in

ches are painted each​ color?
Mathematics
1 answer:
iragen [17]3 years ago
3 0

Answer:

226.285 square

Step-by-step explanation:

Given:

The radius of a circular sign is 12 inches.

Equal parts of the sign are painted red and yellow.

Question asked:

How many square inches are painted each​ color?

Solution:

Here given that <u> a circular sign is divided into two equal parts </u>and one part is painted with red and other with yellow and we have to calculate the area of each color:

We will find area of semicircle of each color:

Area\ of\ semicircle =\frac{\pi x^{2}}{2}

                               =\frac{\frac{22}{7}\times12\times12 }{2} \\ \\ =\frac{\frac{3168}{7} }{2} \\ \\ =\frac{452.57}{2} \\ \\= 226.285\ square\ inches

Thus, 226.285 square inches are painted each color.

                   

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What is the volume of a sphere with a diameter of 5.4 ft, rounded to the nearest tenth of a cubic foot?
Lelechka [254]

Answer:

82.4 ft^3

Step-by-step explanation:

Diameter=5.4ft

Radius=diameter/2

=5.4ft/2

=2.7ft

π=3.14

Volume of a sphere=4/3πr^3

=4/3×3.14×2.7^3

=4/3×3.14×19.683

=4/3×61.80462

=247.21848/3

=82.40616

Approximately

82.4 ft^3

7 0
3 years ago
A survey revealed that 60% of people are entertained by reading books, 50% are entertained by watching TV, and 20% are entertain
Rainbow [258]

Question seem incorrect because 60%,50% and 20% sum up to more than a 100% therefore we've made a little correction

Answer:

0.8

Step-by-step explanation:

Probability = number of favorable outcomes/number of outcomes

Given that 30% are entertained by reading books

50% are entertained by watching TV

20% are entertained by reading books and watching TV

The probability that a person will be entertained by books or TV =

30/100+50/100= 3/10+5/10

=8/10

=0.8

4 0
3 years ago
(3x + 20) (5x) find x
HACTEHA [7]

15x^2+100x


hope this helps

7 0
3 years ago
This is worth 20 points if you don't believe me look down below
Ugo [173]
0.5,2/3,-3/4,1.2,2.3
7 0
3 years ago
Read 2 more answers
The question is:
saul85 [17]
f(x) = \sqrt{x+1} \\ y = \sqrt{x+1} \ or \ y^2 = x+1 \ or \ x = y^2 - 1 \\ Therefore, \ f^{-1}(x)=x^2 - 1

(fof^{-1})(a) = f(f^{-1}(a))=f(a^2-1) \\ =\sqrt{a^2-1+1}=\sqrt{a^2}=a \\  \\ (f^{-1}of)(a)=f^{-1}(f(a))=f^{-1}(\sqrt{a+1})= \\ (\sqrt{a+1})^2-1 = a+1-1 = a

Therefore, (fof^{-1})(a) = (f^{-1}of)(a) = a

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3 years ago
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