Solve the equation on the interval 0 less than or equals theta less than 2 pi 0≤θ<2π. 2 cosine theta plus 1 equals 0 2cosθ+1=
1 answer:
Answer:
θ = 2π/3 or 5π/3
Step-by-step explanation:
2 cosθ + 1= 0
when + 1 goes to R H S Side than it becomes negative by transposition method
2 cos = -1
now by dividing by 2 both sides we get
cosθ = -
since cosθ is negative
Cosθ = - cos 60°
it means either cosθ lies in 2nd or third quadrant
θ = π - π/3
or
θ = 2π- π/3
so θ = 2π/3 or 5π/3
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Answer:
Step-by-step explanation:
The equation of a line is given in the form
Where
m is the slope with formula
and
b is the y-intercept [y axis cutting point of line]
Given the two points (0, -2) and (6,0),
x_1 = 0
y_1 = -2
x_2 = 6
y_2 = 0
Now, we find m using formula:
Now we have
Finding b, we plug in any (x,y) point. Lets put (6,0) and find b:
Thus,
equation of line =