Answer:
For maximum area, all of the wire should be used to construct the square.
The minimum total area is obtained when length of the wire is 10m
Step-by-step explanation:
For maximum, we use the whole length
For minimum,
supposed the x length was used for the square,
the length of the side of the square = x/4m
Area = 
For the equilateral triangle, the length of the side = 
Area = 
Total Area = + 
, therefore it is minimum
x = 10.00m
X=35/6 i hope i helped :-)
I think it’s 6. There are 4 squares and 4 triangles. 2 triangles put together turn into a square, so that would make 2 extra squares. 4+2=6.
(6y - 11)(6y + 11) = ay
² - b |use (a - b)(a + b) = a² - b²
(6y)² - 11² =ay² - b
36y² - 121 = ay² - b |add b to both sides
ay² = 36y² - 121 + b |divide both sides by y² ≠ 0
a = (36y² - 121 + b)/y²
90/300
To make it simpler, make it,out of 100 by dividing it all by 3. This will make it:
30/100
Therefore it is 30%
