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Anuta_ua [19.1K]
3 years ago
12

8x+8(c+8)-6 show work its for my homework i get it but im just making sure i did it right:)

Mathematics
2 answers:
ioda3 years ago
7 0
8x+8c+164-6
=8x+8c+158
katovenus [111]3 years ago
4 0
8x+8c+64-6 *distribute*

8x+8c+58 *add like terms*
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PLEASE PLEASE HELP ME! thank you so so much
viva [34]

Answer:

6π

Step-by-step explanation:

(135/360)×π×4²

(135/360)×π×16

=6π

6 0
3 years ago
I’m stuck and I would really like your help.
Neporo4naja [7]

Answer:

Answer: 1/12

Step-by-step explanation:

2/5x-4=8-3/5x.

We want to tank x out of the denominator by multiplying x on both sides.

2/5-4x=8x-3/5

Now we simplify

-12x=-1

x=1/12

Put x in the equation to check it

6 0
2 years ago
Read 2 more answers
What are the coordinates of point B' if the translation vector (7,-5) is applied to tríangle ABC to produce the image triangle A
guajiro [1.7K]

Answer:

A. -1,2

Step-by-step explanation:

take point B move it 7 units (positive) across the x axis then from there 5 units (negative) down. That point lands on (-1,2) so B’ has the new point of that

5 0
2 years ago
Bobs mom asked how he Had done on his math test . Bob said if you mupily my score by 3 then subtract 40 from they answer , then
amid [387]
Let bob score =x

according to given condition

(3x-40)/2=100

3x-40=200
3x=240
x=80
so bob score =80
8 0
3 years ago
Read 2 more answers
Find the missing side length leave your answers as radicals in the simplest form.
ira [324]

Answer:

Part 1) x=\frac{10\sqrt{3}}{3}\ units

Part 2) y=5\ units

Step-by-step explanation:

step 1

Find the value of x

In the right triangle of the figure

sin(30^o)=\frac{(5\sqrt{3}/3)}{x} ---> opposite side angle of 30 degrees divided by the hypotenuse

Remember that

sin(30^o)=\frac{1}{2}

substitute

\frac{1}{2}=\frac{(5\sqrt{3}/3)}{x}

solve for x

x=\frac{5\sqrt{3}}{3}(2)

x=\frac{10\sqrt{3}}{3}\ units

step 2

Find the value of y

In the right triangle of the figure

cos(30^o)=\frac{y}{x} ---> adjacent side angle of 30 degrees divided by the hypotenuse

we have

x=\frac{10\sqrt{3}}{3}\ units

cos(30^o)=\frac{\sqrt{3}}{2}

substitute

\frac{\sqrt{3}}{2}=\frac{y}{\frac{10\sqrt{3}}{3}}    

y=(\frac{\sqrt{3}}{2})(\frac{10\sqrt{3}}{3})

y=5\ units

4 0
3 years ago
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