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2 years ago

Compare the fractions. Use <, >, or =. 6 1 7 7

Mathematics

1 answer:

AURORKA [14]2 years ago

8 0

Answer:

-6/7 < -1/7

because it is more than negative one by seven

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Grace [21]

Answer:

Solve the equation for y by finding a, b, and c

of the quadratic then applying the quadratic formula.

Exact Form:

y = 3,−9/2

Decimal Form:

y = 3,−4.5

Mixed Number Form:

y = 3,− 4 1/2

Step-by-step explanation:

branliest pls

7 0

1 year ago

Read 2 more answers

A rectangle has an area of 82 ft2. What is<br> the length if the width is 10 ft?

Luda [366]

Answer:

187

Step-by-step explanation:

7 0

2 years ago

What is the inverse of f(x)=x^4+7 for x>0 where function g is the inverse of function f?<br> -

Ann [662]

Answer:

$g(x) = \sqrt[4]{x-7},~ x\geq 7$

Step by step explanation:

$y= f(x) = x^4+7\\\\\text{Replace x with y and solve for y:}\\\\~~~~~~~x = y^4 +7\\\\\implies y^4 = x-7\\\\\implies y = \pm\sqrt[4]{x-7}\\\\ \implies f^{-1}(x) = \pm\sqrt[4]{x-7}$

7 0

1 year ago

Solve y'' + 10y' + 25y = 0, y(0) = -2, y'(0) = 11 y(t) = Preview

svetlana [45]

Answer: The required solution is

$y=(-2+t)e^{-5t}.$

Step-by-step explanation: We are given to solve the following differential equation :

$y^{\prime\prime}+10y^\prime+25y=0,~~~~~~~y(0)=-2,~~y^\prime(0)=11~~~~~~~~~~~~~~~~~~~~~~~~(i)$

Let us consider that

$y=e^{mt}$ be an auxiliary solution of equation (i).

Then, we have

$y^prime=me^{mt},~~~~~y^{\prime\prime}=m^2e^{mt}.$

Substituting these values in equation (i), we get

$m^2e^{mt}+10me^{mt}+25e^{mt}=0\\\\\Rightarrow (m^2+10y+25)e^{mt}=0\\\\\Rightarrow m^2+10m+25=0~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mt}\neq0]\\\\\Rightarrow m^2+2\times m\times5+5^2=0\\\\\Rightarrow (m+5)^2=0\\\\\Rightarrow m=-5,-5.$

So, the general solution of the given equation is

$y(t)=(A+Bt)e^{-5t}.$

Differentiating with respect to t, we get

$y^\prime(t)=-5e^{-5t}(A+Bt)+Be^{-5t}.$

According to the given conditions, we have

$y(0)=-2\\\\\Rightarrow A=-2$

and

$y^\prime(0)=11\\\\\Rightarrow -5(A+B\times0)+B=11\\\\\Rightarrow -5A+B=11\\\\\Rightarrow (-5)\times(-2)+B=11\\\\\Rightarrow 10+B=11\\\\\Rightarrow B=11-10\\\\\Rightarrow B=1.$

Thus, the required solution is

$y(t)=(-2+1\times t)e^{-5t}\\\\\Rightarrow y(t)=(-2+t)e^{-5t}.$

6 0

2 years ago

Hat is the value of x in the equation −x = 3 − 4x + 15? −18 −6 6 18

nadya68 [22]

I believe that x is equal to 6. x=6

7 0

1 year ago