Answer:
Pr(the sum of the numbers rolled is either a multiple of 3 or an even number)=
Step-by-step explanation:
Let A be the event "sum of numbers is multiple of 3"
and B be the event "sum is an even number".
As our dice has six sides, so the sample space of two dices will be of 36 ordered pairs.
|sample space | = 36
Out of which 11 pairs have the sum multiple of 3 and 18 pairs having sum even.
So Pr(A)= 
and Pr(B)= 
and Pr(A∩B) =
, as 5 pairs are common between A and B.
So now Pr(A or B)= Pr(A∪B)
= Pr(A)+Pr(B) - Pr(A∩B)
=
+
- 
= 
= 
The factors of the given model are (x+2) and (x+7)
Given the representation of the model expressed as;

To get the factors, we will factorize the given quadratic function as shown:

Group the functions to have;

Factor out the GCF from both parenthesis:

Hence the factors of the given model are (x+2) and (x+7)
Learn more on factorization here: brainly.com/question/25829061
Answer:
Below in bold.
Step-by-step explanation:
Nth term an = a1 + d(n - 1) where a1 = term 1 and d = common difference.
Here a1 = 5 and d = 8-5 = 3.
So an = 5 + 3(n - 1)
15th term a15
= 5 + 3(15 - 1)
= 5 + 42
= 47.
Answer:
c.
Step-by-step explanation:
Move the constant to the right side and the sign
0.5x=26-6
Calculate
0.5x=26-6=20 >>> 0.5x=20
divide both sides of by the equation 0.5
0.5x=20 >>> x=40