All categories

3 years ago

Need help on answering number 14.

Mathematics

2 answers:

Lana71 [14]3 years ago

6 0

Y is equal to -35, plug in x in the other equation.

olga nikolaevna [1]3 years ago

4 0

Y=7x
If x is equal to -5, and you need to solve for y, you need to plug in -5
Y=7(-5)
Y=-35

You might be interested in

Simplify

Dominik [7]

The correct answer is 'C'

4 0

4 years ago

I’m taking a test rn please I need help!?

Zinaida [17]

Answer:

1. 4 (x +6)

2. 3x + 38

Step-by-step explanation:

hopefully this helps :)

6 0

3 years ago

Could you guys help me in 34 please , I am stuck .<br> I will add points

Sever21 [200]

The answer is (1 3/4, 8 1/4)

This is because if you check the previous values for x and y you can see that you have to add 2/4 to c and y.

Hope this helps!

If it does, it would be helpful to me if you could make me brainliest.

3 0

3 years ago

Draw the graph of the line that is perpendicular to Y= 4X +1 and goes through the point (2, 3)

spayn [35]

Given:

$\begin{gathered} y=4x+1 \\ \text{ point }(2,3) \end{gathered}$

To find:

Draw a graph of a line that is perpendicular to the given line and passing through a given point.

Explanation:

As we know that relation between two slopes of perpendicular slopes of lines:

$m_1.m_2=-1$

Slope of given line y = 4x + 1 is:

$m_2=4$

So, the slope of line perpendicular to given line is:

$m_2=-\frac{1}{4}$

Also, so line equation that is perpendicular to given line is:

$y=-\frac{1}{4}x+c...........(i)$

Also, the required line is passing thorugh given point (2, 3), i.e.,

$\begin{gathered} 3=-\frac{1}{4}(2)+c \\ c=3+\frac{1}{2} \\ c=\frac{7}{2} \end{gathered}$

So, line equation that is perpendicular to given line is:

$y=-\frac{1}{4}x+\frac{7}{2}$

The required graph of line is:

8 0

2 years ago

If the mean of A and B is 20, the mean of B and C is 24 and the mean of A,B and C is 18.What is the mean of A and C?

Zielflug [23.3K]

Answer:

the mean of A and C is 10

Step-by-step explanation:

Given;

mean of A and B = 20

mean of B and C = 24

mean of A, B and C = 18

$\frac{A + B}{2} = 20\\\\A+ B = 40 ---- (1)\\\\\frac{B + C}{2} = 24\\\\B+ C = 48----(2)\\\\\frac{A+ B+ C}{3} = 18\\\\A+ B+ C= 54---(3)\\\\From (1); \ A = 40 - B\\\\From(2); \ C = 48 - B\\\\\Substitute \ the \ values \ of \ A \ and \ C \ into \ (3)\\\\(40-B) + B + (48-B) = 54\\\\simplify;\\\\(40 + 48) + (B-B-B)= 54\\\\88 -B = 54\\\\-B = 54-88\\\\-B = -34\\\\B = 34$

Recall; A = 40 - B

A = 40 - 34

A = 6

Also, C = 48 - B

C = 48 - 34

C = 14

Therefore, the mean of A and C is calculated as;

$= \frac{A + C}{2} \\\\= \frac{6 + 14}{2} \\\\= 10$

5 0

3 years ago