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Alexandra [31]
2 years ago
11

Need help on answering number 14.

Mathematics
2 answers:
Lana71 [14]2 years ago
6 0
Y is equal to -35, plug in x in the other equation.
olga nikolaevna [1]2 years ago
4 0
Y=7x
If x is equal to -5, and you need to solve for y, you need to plug in -5
Y=7(-5)
Y=-35
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PLEASE I NEED HELP.
Musya8 [376]

Answer:

I believe it is D.

Step-by-step explanation:

The associative property switches around the order of the digits to make the problem easier. In my opinion it is easiest to multiply the fractions together, and then the whole number.

7 0
3 years ago
Read 2 more answers
The sketch shows two parallel lines cut by a transversal. Which pair of angles are alternate interior angles?
Likurg_2 [28]

Answer:

B) Angle 5 and angle 4

Step-by-step explanation:

Given

See attachment for sketch

See comment for options

Required

The alternate interior angles

Interior angles are such that they are located between the given parallel lines.

In the attached sketch, the interior angles are: 3, 4, 5 and 6

Alternate angles are at the opposite sides of the transversal

Hence:

<em>4 and 5 are alternate interior</em>

<em>3 and 5 are also alternate interior</em>

5 0
3 years ago
Which is the largest interval over which the function shown in the table is increasing?
vova2212 [387]

Answer:

x < 0

Step-by-step explanation:

If you were to graph the function, you would get a parabola that opens down with the vertex at (0, 0).  So, the graph is increasing from -∞ to 0.

3 0
2 years ago
Which is equivalent to 64 Superscript one-fourth?
Schach [20]

Answer:

2 RootIndex 4 StartRoot 4 EndRoot

Step-by-step explanation:

we have

64^{\frac{1}{4}}

Decompose the number 64 in prime factors

64=2^{6}=2^{4}2^{2}

substitute

64^{\frac{1}{4}}=(2^{4}2^{2})^{\frac{1}{4}}=2^{\frac{4}{4}}2^{\frac{2}{4}}=2\sqrt[4]{4}

7 0
2 years ago
Read 2 more answers
Simplify LaTeX: \Large\frac{-4^{6} \cdot 4^{2}}{4^{4}}
Oksanka [162]

⇨ The value of this <u>simplified expression</u> = -4096/1 or -4096.

<h3>   </h3>
  • To solve this expression, just multiply the power base by how many times indicate the exponent, and then divide the numerator and denominator of the fraction by the same number.

Power or potentiation is a multiplication in equal factors, where there are <em>terms responsible</em> for obtaining the final result. An potency is given by \large \sf a^{n}. The terms of a power are:

<h3>     </h3>
  • Base
  • Exponent
  • equal factors
  • power
<h3>         </h3>

✏️ <u>Resolution/Answer</u>:

\\ \large \sf \dfrac{-4^{6} \cdot 4^{2}}{4^{4}}=\\\\

  • Multiply the powers of the numbers at numerator of the fraction, with the base <em>being multiplied by how many times</em> to indicate the exponent.

\\\large \sf \dfrac{-4^{6} \cdot 4^{2}}{4^{4}}=

\large \sf \dfrac{-4\cdot4\cdot4\cdot4\cdot4\cdot4\cdot 4^{2}}{4^{4}}=

\large \sf \dfrac{-4\cdot4\cdot4\cdot4\cdot16\cdot 4^{2}}{4^{4}}=

\large \sf \dfrac{-4\cdot4\cdot16\cdot16\cdot 4^{2}}{4^{4}}=

\large \sf \dfrac{-16\cdot16\cdot16\cdot 4^{2}}{4^{4}}=

\large \sf \dfrac{-16\cdot16\cdot16\cdot 4\cdot4}{4^{4}}=

\large \sf \dfrac{-16\cdot16\cdot16\cdot 16}{4^{4}}=\\\\

  • <em>Multiply </em>the power at denominator of the fraction:

\\\large \sf \dfrac{-16\cdot16\cdot16\cdot 16}{4^{4}}=

\large \sf \dfrac{-16\cdot16\cdot16\cdot 16}{4\cdot4}=

\large \sf \dfrac{-16\cdot16\cdot16\cdot 16}{16}=\\\\

  • <em>Multiply </em>the numerator numbers together:

\\\large \sf \dfrac{-16\cdot16\cdot16\cdot 16}{16}=

\large \sf \dfrac{-16\cdot16\cdot 256     }{16}=

\large \sf \dfrac{-256\cdot 256     }{16}=

\large \sf \dfrac{- 65536  }{16}=\\\\

  • Simplify the fraction by number 16:

\\\large \sf \dfrac{- 65536  }{16}=

\large \sf \dfrac{- 65536  \div16}{16\div16}=

{\orange{\boxed{\boxed{\pink {\large \displaystyle \sf { \frac{-4096}{1}  \ or \ -4096 }}}}}} \\\\\\

  • So this expression in its simplified form = -4096/1 or -4096.

{\orange{\boxed{\boxed{\pink {\large \displaystyle \sf { \frac{-4096}{1}  \ or \ -4096 }}}}}}\\\\

                                 ★ Hope this helps! ❤️

6 0
2 years ago
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