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Mazyrski [523]
3 years ago
9

Brooke has to set up 70 chairs in equal rows for the class talent show. But, there is not room for more then 20 rows. What are t

he possible number of rows that Brooke could set up?
Mathematics
1 answer:
grin007 [14]3 years ago
7 0

Answer:

The answer is 2, 5, 7, 10, and 14.


Step-by-step explanation:

Let x be the number of rows. There is not room for more than 20 rows:

x ≤ 20


Since all rows must be equal, when we divide 70 by x, we must get a whole number. So, we must find all divisors of 70 smaller or equal to 20 and they are: 2, 5, 7, 10, and 14.

So, the possibilities are:

2 rows with 35 chairs in each row

5 rows with 14 chairs in each row

7 rows with 10 chairs in each row

10 rows with 7 chairs in each row

14 rows with 5 chairs in each row

Hope this helps!!


~CoCo

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A sum of money is divided amongst Farah, Shaiyara and Zahin in the ratio 10: 7: 5. If
r-ruslan [8.4K]

Answers:

  • Total amount of money =  220 dollars
  • Amount Farah gets = 100 dollars

==========================================================

Explanation:

  • F = amount Farah gets
  • S = amount Shaiyara gets
  • Z = amount Zahin gets

The money is divided in the ratio 10:7:5

This means that

  • F = 10x
  • S = 7x
  • Z = 5x

for some positive real number x.

Since Shaiyara gets $20 more than Zahin, we can say,

S = Z+20

Let's plug in S = 7x and Z = 5x and solve for x

S = Z+20

7x = 5x+20

7x-5x = 20

2x = 20

x = 20/2

x = 10

Therefore,

  • F = 10x = 10*10 = 100
  • S = 7x = 7*10 = 70
  • Z = 5x = 5*10 = 50

The ratio F:S:Z becomes 100:70:50 which reduces fully to 10:7:5 after dividing all three parts by the GCF 10.

The total sum of money shared is 100+70+50 = 220 dollars and Farah gets $100 of that total.

6 0
2 years ago
Chase invested $83,000 in an account paying an interest rate of 6.3%
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Answer:145

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Which equations have infinitely many solutions? MORE THAN ONE
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B and D

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At a festival 2/7 of the number of girls was equal to 3/5 of the number of boys. There were 165 fewer boys than girls, how many
koban [17]
X=number of girls.
y=number of boys.
We can suggest this system of equations:
2/7 x=3/5 y ⇒10x=21y   ⇒x=21/10 y
y=x-165 

We can solve this problem by substitution method:
x=(21/10)(x-165)
10x=21x-3465
10x-21x=-3465
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x=-3465 /-11=315

y=x-165=315-165=150

Number of children=number of girls + number of boys
Number of children=315 +150=465

Answer: there were 465 children  at the festival. 
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