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antiseptic1488 [7]
3 years ago
4

Kim solved the equation below by graphing a system of equations. log Subscript 2 Baseline (3 x minus 1) = log Subscript 4 Baseli

ne (x + 8) What is the approximate solution to the equation? 0.6 0.9 1.4 1.6
Mathematics
2 answers:
ohaa [14]3 years ago
5 0

Answer:

1.4

Step-by-step explanation:

C on edge

Luden [163]3 years ago
4 0

Answer:

1.4

Step-by-step explanation:

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On April 1, the price of gas at Bob's Corner Station was $3.35 per gallon. On May 1, the price was $3.85 per gallon. On June 1,
Zina [86]
<h2>Answer:</h2>

1. Between April 1 and May 1, Bob's price incrdased by <u>$0.50 or 15%</u>.

2. Between May 1 and June 1, Bob's price decreased by <u>$0.50 or 13%</u>.

3. Suppose that atgas station across the street, prices are always 20% higher than Bob's. In absolute dollar terms, the difference between Bob's prices and the prices across the street is <u>$0.1 more expensive</u> when gas costs $3.85 than when gas costs $3.35.

4. Suppose the Fed raises the target for the federal fundsb rate from 2% to 2.25%. This change of percentage points means that the Fed raised its target by approximately <u>0.25%</u>.

<h2>Step-by-step explanation:</h2>

<h3>1. Between April 1 and May 1, Bob's price incrdased by...</h3>

<em>Take the difference of the prices to find an absolute value:</em>

$3.85 - $3.35= $0.50.

<em>Use the following formula to find the relative value:</em>

C= |Original value - New value|/ Original value

C=\frac{|OV-NV|}{OV}=\frac{|3.35-3.85|}{3.35}  =0.15=15%.

<h3>2. Between May 1 and June 1, Bob's price decreased by...</h3>

<em>Take the difference of the prices to find an absolute value:</em>

$3.85 - $3.35= $0.50.

<em>Use the following formula to find the relative value:</em>

C= |Original value - New value|/ Original value

C=\frac{|OV-NV|}{OV}=\frac{|3.35-3.85|}{3.85}  =0.13=13%.

<h3>3. Suppose that atgas station across the street, prices are always 20% higher than Bob's. In absolute dollar terms, the difference between Bob's prices and the prices across the street is (blank) when gas costs $3.85 than when gas costs $3.35.</h3>

<em>In this question we are looking for the difference of a difference. </em>

<em>If the proces across the street are always 20% higher, to find how much the gallon costs just multiply the price by 1.20, to increase 0.2 or 20%:</em>

$3.85 * 1.20= $4.62.

<em>Now, to see how much expensive this price is compared to Bob's, take de difference between the prices:</em>

$4.62 - $3.85= $0.77.

<em>Do the same to find the difference between the gas prices when the price is $3.35.</em>

$3.35 * 1.20= $4.02.

$4.02 - $3.35= $0.67.

Now, find the difference of those differences:

$0.77 - $0.67= $0.1.

<h3>4. Suppose the Fed raises the target for the federal funds rate from 2% to 2.25%. This change of percentage points means that the Fed raised its target by approximately (blank).</h3>

<em>Find the difference between percentages:</em>

2.25% - 2%= 0.0225 - 0.02= 0.0025= 0.25%.

<em>Simpler method:</em>

2.25% - 2%= 0.25%.

3 0
2 years ago
If f(1) = 160 and f(n + 1) = –2f(n), what is f(4)?
sashaice [31]
Hello,

f(1)=160
f(2)=160*(-2)
f(3)=160*(-2)²
f(4)=160*(-2)^3=-1280

f(n)=160*(-2)^(n-1)


8 0
3 years ago
Read 2 more answers
What is the rate of change of the function y = 7/4x+1?
Leokris [45]

Answer:

7/4!

Step-by-step explanation:

I think?

6 0
3 years ago
What is the ordered pair for point A in this coordinate plane?
Alecsey [184]

Answer:

the answer is A.

Step-by-step explanation:

left 7       (-7)

down 5   (-5)


the coordinates are(-7,-5)

4 0
3 years ago
The path of a projectile launched from a 16-ft-tall tower is modeled by the equation y = −16t2 + 64t +16. What is the maximum he
Aleks04 [339]

Answer:

<h3>80 feet</h3>

Step-by-step explanation:

Given the path of a projectile launched from a 16-ft-tall tower modeled by the equation y = −16t^2 + 64t +16

h is the maximum height reached

t is in seconds

The velocity of the projectile at its maximum height is zero;

velocity v = dy/dt

v = -32t + 64

Since v = 0 at maximum height

0 = -32t + 64

32t = 64

t = 2secs

Substitute t = 2secs into the equation of the height to get the maximum height.

y = −16t^2 + 64t +16

at t = 2secs

y = −16(2)^2 + 64(2) +16

y = -64 + 128 + 16

y = 64+16

y = 80 feet

Hence the maximum height, in feet, reached by the projectile is 80 feet

5 0
3 years ago
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