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Allisa [31]
3 years ago
8

What is the ordered pair for point A in this coordinate plane?

Mathematics
1 answer:
Alecsey [184]3 years ago
4 0

Answer:

the answer is A.

Step-by-step explanation:

left 7       (-7)

down 5   (-5)


the coordinates are(-7,-5)

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Write an equation that represents the following statement. Five less than the product of r and two is 3.
liraira [26]
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2 years ago
SOMEONE HELPP ME ASAP
Naily [24]

Answer:

k = 7

Step-by-step explanation:

The given figures are lines f(x) and g(x)

For the line f(x), we have the y-intercept at (0, -3) and slope = (-1 - (-3))/(-3 - 0) = -2/3

Therefore, line f(x) = y - (-3) = -2/3·(x - 0) which gives f(x) = y = -3 - 2·x/3

For the line g(x), the y-intercept is (0, 4), and the slope is (4 - 2)/(0 - 3) = -2/3

The equation of the line g(x) is therefore, g(x) = y - 4 = -2/3·x, which simplifies to the slope and intercept form as g(x) = y = 4 - 2/3·x

Therefore, given that the transformation of f(x) to g(x) is given as g(x) = f(x) + k, we have;

k = g(x) - f(x) = 4 - 2/3·x - (-3 - 2·x/3) = 4 - 2/3·x + 3 + 2·x/3 = 7

∴ k = 7

4 0
3 years ago
. If f(x) = 7x2 – 3x + 7, find f(2) + f(–1) + f(0).​
alexandr402 [8]
<h2>♪Answer : </h2>

»f(x) = 7x² - 3x + 7

  • find f(2) in f(x)

»f(2) = 7(2)² - 3(2) + 7

»f(2) = 7(4) - 6 + 7

»f(2) = 28 - 6 + 7

»f(2) = 29

  • find f(-1) in f(x)

»f(-1) = 7(-1)² - 3(-1) + 7

»f(-1) = 7(1) + 3 + 7

»f(-1) = 7 + 3 + 7

»f(-1) = 17

  • find f(0) in f(x)

»f(0) = 7(0)² - 3(0) + 7

»f(0) = 7(0) - 0 + 7

»f(0) = 0 - 0 + 7

»f(0) = 7

so, f(2) + f(-1) + f(0) is

  • 29 + 17 + 7
  • = 53✅
7 0
3 years ago
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