True! they are corresponding angles.
<h3>Radius = 14cm</h3>
Step-by-step explanation:
Let O be the centre of the circle. Since P and S are the points of contact of tangents AD and DC respectively, OP ⊥ AD and OS ⊥ DC
Also, AD ⊥ DC (given), therefore, OPDS is a square.
BR = BQ = 27cm...(tangents from an external point to a circle are equal in length)
therefore, CR = CB - BR = (38 - 27)cm = 11cm
SC = CR = 11 cm...(tangents from an external point) therefore, DS = DC - SC = (25 - 11) cm = 14 cm.
therefore,
Radius of a circle = OP = DS = 14 cm...(therefore, OPDS is a square).
<h3>Hope it helps you!! </h3>
The area of the square is 9, the area of all the semi circles added together is 15.7, when you add them together you get 24.7
I would say F cause a triangle sides add up to 180
