Question

VERY URGENT. BRAINLIEST TO FIRST CORRECT ANSWER ASAP.

Answer 1

Answer:

B. 2 x 10^2 m^3

Step-by-step explanation:

Given

Volume of submarine when full of water= 7.8 × 10³ m³

Total mass of submarine =8× 10⁶ kg

Density of sea water= 1000 kg/m³

Volume to be occupied by sea water at given mass of  submarine=?

Apply; Density=mass/volume ⇒⇒volume=mass/density

where M=mas, V=volume, D=density

$V=\frac{M}{D} \\\\\\\\V=\frac{8*10^6}{10^3} =8*10^3$

Excess volume= 8×10³ - 7.8× 10³ = 2×10² m³