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grin007 [14]
3 years ago
7

Alien probe is stretched between the top and a stake in the ground the head of the state is at ground level the rope also touche

s a tree that is growing halfway between the steak in building if the tree is 16 feet tall how tall is the building
Mathematics
1 answer:
Aleksandr-060686 [28]3 years ago
6 0
The building is about 20 to 21 feet tall.

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Let [n] = 1 if n is odd and 0 if n is even, for all positive integer n. if [n] * [n+8] = 0, then what is one possible value of n
astra-53 [7]
[n][n+8]=0

if either or both of [n] and [n+8] are 0, i.e. if one or both of n and n+8 are even. But both will be even if n is even, and odd otherwise, so any even n will be a solution, e.g. n=2.
5 0
3 years ago
F(x)=x^2-8x+7 in factored form​
Karolina [17]

Answer:

(x-1)(x-7)

Step-by-step explanation:

To factor the equation, find two binomials which multiply to a quadratic. The quadratic's factors are found by finding two numbers that multiply to 7 and add to -8.

-1 and -7 multiply to 7 and add to -8.

(x-1)(x-7)

7 0
3 years ago
Find the value for the variable expression p + 5 when p = 2.
sweet [91]
Replace all the variables with their values. In this case, we know the value of the variable p.

Now the expressions p + 5 becomes 2 + 5.

2 + 5 = 7

So, C. 7 is the answer.
7 0
3 years ago
Read 2 more answers
Find the smallest 4 digit number such that when divided by 35, 42 or 63 remainder is always 5
alex41 [277]

The smallest such number is 1055.

We want to find x such that

\begin{cases}x\equiv5\pmod{35}\\x\equiv5\pmod{42}\\x\equiv5\pmod{63}\end{cases}

The moduli are not coprime, so we expand the system as follows in preparation for using the Chinese remainder theorem.

x\equiv5\pmod{35}\implies\begin{cases}x\equiv5\equiv0\pmod5\\x\equiv5\pmod7\end{cases}

x\equiv5\pmod{42}\implies\begin{cases}x\equiv5\equiv1\pmod2\\x\equiv5\equiv2\pmod3\\x\equiv5\pmod7\end{cases}

x\equiv5\pmod{63}\implies\begin{cases}x\equiv5\equiv2\pmod 3\\x\equiv5\pmod7\end{cases}

Taking everything together, we end up with the system

\begin{cases}x\equiv1\pmod2\\x\equiv2\pmod3\\x\equiv0\pmod5\\x\equiv5\pmod7\end{cases}

Now the moduli are coprime and we can apply the CRT.

We start with

x=3\cdot5\cdot7+2\cdot5\cdot7+2\cdot3\cdot7+2\cdot3\cdot5

Then taken modulo 2, 3, 5, and 7, all but the first, second, third, or last (respectively) terms will vanish.

Taken modulo 2, we end up with

x\equiv3\cdot5\cdot7\equiv105\equiv1\pmod2

which means the first term is fine and doesn't require adjustment.

Taken modulo 3, we have

x\equiv2\cdot5\cdot7\equiv70\equiv1\pmod3

We want a remainder of 2, so we just need to multiply the second term by 2.

Taken modulo 5, we have

x\equiv2\cdot3\cdot7\equiv42\equiv2\pmod5

We want a remainder of 0, so we can just multiply this term by 0.

Taken modulo 7, we have

x\equiv2\cdot3\cdot5\equiv30\equiv2\pmod7

We want a remainder of 5, so we multiply by the inverse of 2 modulo 7, then by 5. Since 2\cdot4\equiv8\equiv1\pmod7, the inverse of 2 is 4.

So, we have to adjust x to

x=3\cdot5\cdot7+2^2\cdot5\cdot7+0+2^3\cdot3\cdot5^2=845

and from the CRT we find

x\equiv845\pmod2\cdot3\cdot5\cdot7\implies x\equiv5\pmod{210}

so that the general solution x=210n+5 for all integers n.

We want a 4 digit solution, so we want

210n+5\ge1000\implies210n\ge995\implies n\ge\dfrac{995}{210}\approx4.7\implies n=5

which gives x=210\cdot5+5=1055.

5 0
3 years ago
HELP
kupik [55]

Answer:

The graph of a linear equation forms a straight line, whereas the graph for a non-linear relationship is curved. ... A non-linear relationship reflects that each unit change in the x variable will not always bring about the same change in the y variable

5 0
3 years ago
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