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3 years ago

7

Alien probe is stretched between the top and a stake in the ground the head of the state is at ground level the rope also touche

s a tree that is growing halfway between the steak in building if the tree is 16 feet tall how tall is the building

1 answer:

Aleksandr-060686 [28]3 years ago

6 0

The building is about 20 to 21 feet tall.

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ACB = DCE<br> A = 3x-10, C = 45°, D = 2x+10<br> Please help confused

NemiM [27]

Answer:

x = 20

Step-by-step explanation:

The congruence statement tells you that angle A is congruent to angle D. (Both are listed first in the triangle names.) This means ...

∠A = ∠D

3x -10 = 2x +10

x = 20 . . . . . . . . . . add 10-2x to both sides

6 0

3 years ago

Which quadratic expression represents the product of these factors?

Sladkaya [172]

The answer is C.

-8x^2-6x+35

8 0

3 years ago

Consider the inequality -50x 7) -10. Write an inequality representing the solution for x.

marta [7]

I might be wrong but x should be -360

8 0

3 years ago

What are the lengths of the legs of a right triangle in which one acute angle measures 19o and the hypotenuse is 15 units long?

WITCHER [35]

$x,y-\ lengths\ of\ legs\\\\sin19^\circ=\frac{x}{15}\\\\ sin19^\circ*15=x\\\\0,32*15=x\\\\x=4,8\\\\
y^2+(4,8)^2=15^2\\\\y^2=225-23,04\\\\ y^2=201,96\\\\y=14,2\\\\Legs\ are\ equalt\ to:\ 4,8 \ and\ 14,2.$

6 0

4 years ago

What are the roots of the quadratic equation below 3x2+15x-5=0

fomenos

Answer:

<h2>A</h2><h2 />

Step-by-step explanation:

$3x^2+15x-5=0\\a = 3\\b = 15\\c = -5\\ x = -b\±\frac{\sqrt{b^{2} -4ac} }{2a} \\x = -(15)\±\frac{\sqrt{15^{2} -4(3)(-5)} }{2(3)} \\x = -15 \±\frac{\sqrt{225+60} }{6} \\x = -15\±\frac{\sqrt{285} }{6} = A$

8 0

3 years ago