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3 years ago

Sydney planted 5/9 of her fall flowers. she had 63 unplanted flowers to start how many flowers does she have left to plant

1 answer:

6 0

Since Sydney has planted 5/9 of her flowers and there were 63 flowers that are left unplanted, the first thing we are going to determine is the number of flowers that were planted. To do this, we just have to do the cross multiplication process.
So 5/9 x ?/63 = 35. Therefore, the number of plants planted were 35. To start, Sydney has a total of 100 flowers to be planted. That would be 35 + 65 is 100.

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Avery has 5 more than twice as many dolls as Caraleigh. Avery has 13 dolls in her collection. write an equation to represent the

tamaranim1 [39]

13=2c+5
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3 years ago

Can someone please answer step by step?

alukav5142 [94]

Answer:

George is correct

Step-by-step explanation:

if the jacket is in sales for 20% off, Jane's coupon would give her a discount of 10% on top of the already discounted 20%.

Jane is incorrect because, if she added the 2 discount together, she gets a total of 30%, but that is a 30% discount of the original price of $75 which isn't correct. what we want to do is find how much the jacket cost after 20% discount THEN use the coupon to get a further 10% discount on the sales price of the jacket. and for this reason, George is correct.

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3 years ago

In a Venn diagram, the rectangle represents the entire group. True False

prohojiy [21]

True because the rectangle represents the universe and closed figures.

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3 years ago

Read 2 more answers

What is 45times 67 i need to know please help meeeeeee

Readme [11.4K]

Answer:

3015

Step-by-step explanation:

45×67

is equal to Three thousand & fifteen

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3 years ago

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Use sigma notation to represent the sum of the first seven terms of the following sequence -4,-6,-8.....

lina2011 [118]

Answer:Answer:

$\sum\left {{7} \atop {1}} \right -n(3+n)$

Step-by-step explanation:

Given the sequence -4,-6,-8..., in order to get sigma notation to represent the sum of the first seven terms of the sequence, we need to first calculate the sum of the first seven terms of the sequence as shown;

The sum of an arithmetic series is expressed as $S_n = \frac{n}{2}[2a+(n-1)d]$

n is the number of terms

a is the first term of the sequence

d is the common difference

Given parameters

n = 7, a = -4 and d = -6-(-4) = -8-(-6) = -2

Required

Sum of the first seven terms of the sequence

$S_7 = \frac{7}{2}[2(-4)+(7-1)(-2)]\\\\S_7 = \frac{7}{2}[-8+(6)(-2)]\\\\S_7 = \frac{7}{2}[-8-12]\\\\\\S_7 = \frac{7}{2} * -20\\\\S_7 = -70$

The sum of the nth term of the sequence will be;

$S_n = \frac{n}{2}[2(-4)+(n-1)(-2)]\\\\S_n = \frac{n}{2}[-8+(-2n+2)]\\\\S_n = \frac{n}{2}[-6-2n]\\\\S_n = \frac{-6n}{2} - \frac{2n^2}{2}\\S_n = -3n-n^2\\\\S_n = -n(3+n)$

The sigma notation will be expressed as $\sum\left {{7} \atop {1}} \right -n(3+n)$ . <em>The limit ranges from 1 to 7 since we are to find the sum of the first seven terms of the series.</em>

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3 years ago