Answer:
I tried P as the Principle invested: 750, i, as the interest rate per compounding period = 8.2/100 = 0.082 n, number of compounding periods = 2, and t, time is 6 (6 months before July 1 from January 1?) Because I got 1931.03 and it's wrong:
Step-by-step explanation:
Answer: 0.04 meters
Step-by-step explanation:
Convert cm to meters by dividing the length by 100.
4/100= = 0.04
Answer:
y = -3x + 2
Step-by-step explanation:
The linear equation is in the form
y = mx + b
where m is the slope and b is the y-intercept
the slope can be calculated using two points
Let us have; (-2,8) and (0,2)
The equation of the slope is ;
m = (y2-y1)/(x2-x1) = (2-8)/(0+2) = -6/2 = -3
So for the y-intercept, we select any of the points to substitute
Let us have (0,2)
Substitute this into;
y = -3x + b
2 = -3(0) + b
b = 2
So the equation is;
y = -3x + 2
The equations (2) and (3) you referred to are unavailable, but it is clear that you are trying to show that two set of solutions y1 and y2, to a (second-order) differential equation are solutions, and form a fundamental set. This will be explained.
Answer:
SOLUTION OF A DIFFERENTIAL EQUATION.
Two functions y1 and y2 are set to be solutions to a differential equation if they both satisfy the said differential equation.
Suppose we have a differential equation
y'' + py' + qy = r
If y1 satisfies this differential equation, then
y1'' + py1' + qy1 = r
FUNDAMENTAL SET OF DIFFERENTIAL EQUATION.
Two functions y1 and y2 are said to form a fundamental set of solutions to a second-order differential equation if they are linearly independent. The functions are linearly independent if their Wronskian is different from zero.
If W(y1, y2) ≠ 0
Then solutions y1 and y2 form a fundamental set of the given differential equation.
