First you have to know BODMAS/BIDMAS (idk if all schools teach it like this) but this is the order in which you complete questions so it’s Brackets, Indices, Division/Multiplication, Addition/Subtraction
a) 5^2 is 5x5 which equals 25 1 to the power of anything is always 1 and 2^4 is 2x2x2x2 which is 16
So 5^2-1^5x2^4 = 25-1x16 which is then 25-16 = 9
b) 7^2+4^3 divided by 2^5 so 7^2 is 7x7 which = 49 then 4^3 means 4x4x4 = 64 and 2^5 is 2x2x2x2x2 which equals 32 so
7^2+4^3 divides by 2^5 is 49+64/32 = 49+2 which is 51
Answer: Equilateral triangles are also right triangles sometimes. All angles of an equilateral are congruet sometimes.
Lets just convert them into improper fractions.
1) 4 and 1/12 = 49/12.
1 and 3/4 = 7/4.
2) 7/4 = 21/12
3) 21/12 + 49/12 = 70/12
Back to mixed fractions!
70/12 = 5 and 10/12 = 5 and 5/6
=5 5/6
⭐ Answered by Foxzy0⭐
⭐ Brainliest would be appreciated, I'm trying to reach genius! ⭐
⭐ If you have questions, leave a comment, I'm happy to help! ⭐
There is another method if you want to know. You can simply just do 4 + 1 = 5. Then do 1/12 + 3/4 = 10/12 = 5/6. So it goes to 5 5/6. Your choice which ever you find more eas.
3 √10
I think since a^2+b^2=c^2
To be able to solve this question, we need to know about the Pythagorean theorem: a² + b² = c². A and b represents the two sides that make the right angle, and C represents the hypotenuse, or the longest side, of the triangle.
We know that the hypotenuse is the longest side of the triangle, so that means 9 is c. One side of the triangle is 6, and we have to solve for b. That means 6 is a. We can plug in our values to the formula like this:
Now that we have our equation down, we know what we have to do next: subtract 81 from 36 to get b².
