Answer:
Step-by-step explanation:
4) x² - 14x + 48
We would find two numbers such that their sum or difference is -14x and their product is 48x².
The two numbers are - 6x and - 8x. Therefore,
x² - 6x - 8x + 48
x(x - 6) - 8(x - 6)
(x - 8)(x - 6)
5) 2x² + 21x - 11
We would find two numbers such that their sum or difference is 21x and their product is - 22x².
The two numbers are 22x and - x. Therefore,
2x² + 22x - x - 11
2x(x + 11) - 1(x + 11)
(2x - 1)(x + 11)
6) 5a² - 125
5 is a common factor. So we would factorize 5. It becomes
5(a² - 25)
Simplifying further, it becomes
5(a + 5)(a - 5)
In a triangle, the three interior angles always add to 180°
m∠R + m∠S + m∠<span>T = 180
</span><span>(2x+10) + (2x+25) + (x-5) = 180
</span>2x+10 + 2x+25 + x-5 = 180
5x + 30 = 180
5x = 150
x = 30
Answer:
The time taken for the flare to hit the ground is approximately 10.7 seconds.
Step-by-step explanation:
Given : Suppose a flare is shot from the top of a 120 foot building at a speed of 160 feet per second. The equation
models the h height at t seconds of the flare.
To find : How long will it take for the flare to hit the ground?
Solution :
The equation
models the h height at t seconds of the flare.
The flare to hit the ground when h=0.
Substitute in the equation,

Applying quadratic formula, 
Where, a=-16, b=160 and c=120





Reject the negative value.
Therefore, the time taken for the flare to hit the ground is approximately 10.7 seconds.
Answer:
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Step-by-step explanation:
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Answer:
The base is: ![3 \sqrt[3]{4}](https://tex.z-dn.net/?f=3%20%5Csqrt%5B3%5D%7B4%7D)
Step-by-step explanation:
Given
![f(x) = \frac{1}{4}(\sqrt[3]{108})^x](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Cfrac%7B1%7D%7B4%7D%28%5Csqrt%5B3%5D%7B108%7D%29%5Ex)
Required
The base
Expand 108
![f(x) = \frac{1}{4}(\sqrt[3]{3^3 * 4})^x](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Cfrac%7B1%7D%7B4%7D%28%5Csqrt%5B3%5D%7B3%5E3%20%2A%204%7D%29%5Ex)
Rewrite the exponent as:

Expand


Rewrite as:
![f(x) = \frac{1}{4}(3 \sqrt[3]{4})^x](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Cfrac%7B1%7D%7B4%7D%283%20%5Csqrt%5B3%5D%7B4%7D%29%5Ex)
An exponential function has the following form:

Where

By comparison:
![b =3 \sqrt[3]{4}](https://tex.z-dn.net/?f=b%20%3D3%20%5Csqrt%5B3%5D%7B4%7D)
So, the base is: ![3 \sqrt[3]{4}](https://tex.z-dn.net/?f=3%20%5Csqrt%5B3%5D%7B4%7D)