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kotykmax [81]
3 years ago
8

Ms. Johnson earns $47,000 per year. She is paid weekly and puts 8% of her salary

Mathematics
1 answer:
Gekata [30.6K]3 years ago
3 0
You divide 47,000 by 8. You should get 5,875. That should be the answer
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Please help Factor completely. Show your work (as much work as possible, including a ​list of factors if
Elena-2011 [213]

Answer:

Step-by-step explanation:

4) x² - 14x + 48

We would find two numbers such that their sum or difference is -14x and their product is 48x².

The two numbers are - 6x and - 8x. Therefore,

x² - 6x - 8x + 48

x(x - 6) - 8(x - 6)

(x - 8)(x - 6)

5) 2x² + 21x - 11

We would find two numbers such that their sum or difference is 21x and their product is - 22x².

The two numbers are 22x and - x. Therefore,

2x² + 22x - x - 11

2x(x + 11) - 1(x + 11)

(2x - 1)(x + 11)

6) 5a² - 125

5 is a common factor. So we would factorize 5. It becomes

5(a² - 25)

Simplifying further, it becomes

5(a + 5)(a - 5)

5 0
3 years ago
PLEASE HELP! URGENT! 35 POINTS!
cluponka [151]
In a triangle, the three interior angles always add to 180°

m∠R + m∠S + m∠<span>T = 180

</span><span>(2x+10) + (2x+25) + (x-5) = 180
</span>2x+10 + 2x+25 + x-5 = 180
5x + 30 = 180
5x = 150
x = 30
5 0
3 years ago
Read 2 more answers
Suppose a flare is shot from the top of a 120 foot building at a speed of 160 feet per second. The equation h = ?16t + 160t + 12
insens350 [35]

Answer:

The time taken for the flare to hit the ground is approximately 10.7 seconds.

Step-by-step explanation:

Given : Suppose a flare is shot from the top of a 120 foot building at a speed of 160 feet per second. The equation h =- 16t^2+ 160t + 120 models the h height at t seconds of the flare.

To find : How long will it take for the flare to hit the ground?

Solution :

The equation  h =- 16t^2+ 160t + 120 models the h height at t seconds of the flare.

The flare to hit the ground when h=0.

Substitute in the equation,

-16t^2+ 160t + 120=0

Applying quadratic formula, x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

Where, a=-16, b=160 and c=120

x=\frac{-160\pm\sqrt{160^2-4(-16)(120)}}{2(-16)}

x=\frac{-160\pm\sqrt{33280}}{-32}

x=\frac{-160\pm 182.42}{-32}

x=\frac{-160+182.42}{-32},\frac{-160-182.42}{-32}

x=−0.70,10.70

Reject the negative value.

Therefore, the time taken for the flare to hit the ground is approximately 10.7 seconds.

4 0
3 years ago
Please help i will give brainliest :)
dmitriy555 [2]

Answer:

lollololololololol

Step-by-step explanation:

mark me brainliest :)))

7 0
3 years ago
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What is the simplified base of the function f(x) = One-fourth (Root Index 3 StartRoot 108 EndRoot) Superscript x?
Rainbow [258]

Answer:

The base is: 3 \sqrt[3]{4}

Step-by-step explanation:

Given

f(x) = \frac{1}{4}(\sqrt[3]{108})^x

Required

The base

Expand 108

f(x) = \frac{1}{4}(\sqrt[3]{3^3 * 4})^x

Rewrite the exponent as:

f(x) = \frac{1}{4}(3^3 * 4)^\frac{1}{3}^x

Expand

f(x) = \frac{1}{4}(3^3^\frac{1}{3} * 4^\frac{1}{3})^x

f(x) = \frac{1}{4}(3 * 4^\frac{1}{3})^x

Rewrite as:

f(x) = \frac{1}{4}(3 \sqrt[3]{4})^x

An exponential function has the following form:

f(x)=ab^x

Where

b \to base

By comparison:

b =3 \sqrt[3]{4}

So, the base is: 3 \sqrt[3]{4}

4 0
3 years ago
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