The work done (in foot-pounds) in stretching the spring from its natural length to 0.7 feet beyond its natural length is 1.23 foot-pound
<h3>Data obtained from the question</h3>
From the question given above, the following data were obtained:
- Force (F) = 3 pounds
- Extension (e) = 0.6 feet
- Work done (Wd) =?
<h3>How to determine the spring constant</h3>
- Force (F) = 3 pounds
- Extension (e) = 0.6 feet
- Spring constant (K) =?
F = Ke
Divide both sides by e
K = F/ e
K = 3 / 0.6
K = 5 pound/foot
Thus, the spring constant of the spring is 5 pound/foot
<h3>How to determine the work done</h3>
- Spring constant (K) = 5 pound/foot
- Extention (e) = 0.7 feet
- Work done (Wd) =?
Wd = ½Ke²
Wd = ½ × 5 × 0.7²
Wd = 2.5 × 0.49
Wd = 1.23 foot-pound
Therefore, the work done in stretching the spring 0.7 feet is 1.23 foot-pound
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Answer:
y=5x
Step-by-step explanation:
From (2,10) you rise 25 in the y direction and run 5 in the x direction to get to the next known point (7,35).
Thus, the slope is y=25/5x AKA y=5x
Answer:
y = 12 
Step-by-step explanation:
The standard form of the exponential function is
y = a 
Find a and b by substituting ordered pairs from the table into the equation
Using (0, 12 ), then
12 = a
( = 1 ), so
a = 12, then
y = 12 
Using (1, 34.8 ) , then
34.8 = 12 
( divide both sides by 12 )
b = 2.9
Thus exponential function is
y = 12
Answer:
what do you need help with
Step-by-step explanation:
Answer:
m=13
Step-by-step explanation:
