Answer:
a. the output (y) values of the relation
Step-by-step explanation:
The range of a function is the set of all possible values that a dependent variable would take.
Therefore, it is the output values of the relation.
Answer:
25
Step-by-step explanation:
1/5× 150= 30
1/3× 150= 50
3/10×150= 45
30+50+45= 125
150-125= 25
25 are green
It would be 104? I don’t understand the question but I guessing you’re adding
The real solution of the given equation by factoring x² = 5(x + 210) will be -30 and 35.
<h3>What are the roots of an equation?</h3>
The roots of an equation are the solution of that equation since an equation consists of hidden values of the variable to determine them by different processes and then the resultant is called roots.
As per the given equation,
x² = 5(x + 210)
x² = 5x + 1050
x² - 5x - 1050 = 0
x² - 35x + 30x - 1050 = 0
x(x - 35) + 30(x - 35) = 0
(x + 30)(x - 35) = 0
x = -30 and x = 35
Hence "The real solution of the given equation by factoring x² = 5(x + 210) will be -30 and 35".
To learn more about the roots of equations,
brainly.com/question/12029673
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Imagine the unit circle. The cot(theta) is a line from (0,1) to (-4,1). Imagine it is part of a triangle with the origin (draw it!).
Then the hypotenuse length is √(1+4²) = √17.
The sine rule says that sin(90)/√17 must equal sin(theta)/4, and sin(90)=1, so
