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Scorpion4ik [409]
2 years ago
15

If ΔABC ≅ ΔDEF, then what corresponding parts are congruent?

Mathematics
1 answer:
labwork [276]2 years ago
5 0

Answer:

its A.

Step-by-step explanation:

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<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bb%5E%7B-2%7D%20%7D%7Bb%5E%7B4%7D%20%7D" id="TexFormula1" title="\frac{b^{-2} }{b^{4}
MAXImum [283]

Answer: \frac{1}{b^6}   or b^{-6}  

Step-by-step explanation:

\frac{b^-2+2}{b^4+2}   Add the exponent two to both sides.  After adding -2 and     2 you get 0 and any number raised to the zero power is one. And 4 plus two is 6

\frac{b^0}{b^6}   = \frac{1}{b^6}

3 0
3 years ago
If the area of a baseball diamond (shape of a square) is 8100 ft squared, how would you find the distance from 1st base to 3rd b
Readme [11.4K]

Answer:

  • Exact distance = 90\sqrt{2} feet
  • Approximate distance = 127.2792 feet.

===========================================================

Explanation:

The area of the square is 8100 square feet, abbreviated ft^2.

Apply the square root to find the distance from any base to its adjacent counterpart (eg: from 1st to 2nd base). So we get sqrt(8100) = 90 ft as that side distance. Notice that 90*90 = 8100.

If you were to draw a line from 1st base to 3rd base, then you would split the square into two congruent right triangles. Each right triangle is isosceles (the two legs being 90 ft each).

Use the pythagorean theorem to find the hypotenuse.

a^2 + b^2 = c^2\\\\c = \sqrt{a^2+b^2}\\\\c = \sqrt{90^2+90^2}\\\\c = \sqrt{2*90^2}\\\\c = \sqrt{2}*\sqrt{90^2}\\\\c = \sqrt{2}*90\\\\c = 90\sqrt{2} \ \text{ ... exact distance}\\\\c \approx 127.2792 \ \text{ ... approximate distance}\\\\

The distance from 1st to 3rd base is roughly 127.2792 feet.

5 0
2 years ago
connie sells lemonade for $0.25 per small cup and $0.75 per large cup. if she sells 20 small cups how many large ones must she s
Nady [450]

Answer:34

Step-by-step explanation:

8 0
3 years ago
Evaluate the expression. 34⋅23
Alex17521 [72]

Answer:

784

Step-by-step explanation:

(30+4)(23+3)

7 0
3 years ago
If (x + 2 ) is a factor of x3 − 6x2 + kx + 10, k =
BartSMP [9]
If a binomial x-a is a factor of a polynomial p(x), then p(a)=0.

x+2 is a factor of p(x)=x³-6x²+kx+10, so p(-2)=0.

p(-2)=0 \\&#10;(-2)^3 - 6 \times (-2)^2 + k \times (-2) + 10=0 \\&#10;-8-6 \times 4-2k+10=0 \\&#10;-8-24-2k+10=0 \\&#10;-2k-22=0 \\&#10;-2k=22 \\&#10;k=\frac{22}{-2} \\&#10;\boxed{k=-11}
8 0
3 years ago
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