The solution to the problem is as follows:

arc sin (sin 3pi) = theta
where theta is the angle ur looking for 
so that becomes 
sin (theta) = sin 3pi 
sin (theta) = 0 
theta = 0, pi

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

6 0

2 years ago

Based on data collected from its production processes, Crosstiles Inc. determines that the breaking strength of its most popular

alexandr1967 [171]

Answer:

16% of its popular porcelain tile will have breaking strengths greater than 412.5 pounds per square inch.

Step-by-step explanation:

We are given that the breaking strength of its most popular porcelain tile is normally distributed with a mean of 400 pounds per square inch and a the standard deviation of 12.5 pounds per square inch.

Let X = the breaking strength of its most popular porcelain tile

SO, X ~ Normal( $\mu=400,\sigma^{2}=12.5^{2}$ )

The z score probability distribution for normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = mean breaking strength of porcelain tile = 400 pounds per square inch

$\sigma$ = standard deviation = 12.5 pounds per square inch

Now, probability that the popular porcelain tile will have breaking strengths greater than 412.5 pounds per square inch is given by = P(X > 412.5)

P(X > 412.5) = P( $\frac{X-\mu}{\sigma}$ > $\frac{412.5-400}{12.5}$ ) = P(Z > 1) = 1 - P(Z $\leq$ 1)

= 1 - 0.84 = 0.16

Therefore, 16% of its popular porcelain tile will have breaking strengths greater than 412.5 pounds per square inch.

7 0

2 years ago