Step-by-step explanation:
Chord AB and Chord CD are equidistant from the center of the circle.

Answer:
0.0087 probability that a freshman non-Statistics major and then a junior Statistics major are chosen at random
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
What is the probability that a freshman non-Statistics major and then a junior Statistics major are chosen at random?
There are 5 freshman non-Statistics majors out of 102 students.
Then, there will be 18 junior statistics majors out of 101 students(1 will have already been chosen). So

0.0087 probability that a freshman non-Statistics major and then a junior Statistics major are chosen at random
Step-by-step explanation:
4(a-3)=22
a-3=4-22
a-3=18
a=18+3
a=21
5(x-6)=65
x-6=65-5
x-6=60
×=60+6
x=66
hope it will help u...............
Answer:
f^-1(x) = (x -14)/10
Step-by-step explanation:
You can find the inverse function by solving for y:
x = f(y)
Here, that is ...
x = 10y +14 . . . . . use the definition of f(y)
x -14 = 10y . . . . . . subtract 14
(x -14)/10 = y . . . . divide by the coefficient of y
So, your inverse function is ...
f^-1(x) = (x -14)/10
Answer:
1 pound of avocado costs $1.8.
Step-by-step explanation:
This problem is just a simple division problem. We jest need to divide the given values to get the answer. For our problem, to know the price of 1 pound of avocado, we need to divide the $9 by 5 since the problem stated that the price of 5 pounds of avocados is $9.
Given:
5 pounds avocados = $9
Required:
cost of 1 pound of avocado
Solution:
$9 / 5 pounds = $1.8/pound
1 pound avocado = $1.8
Notice from the first line of solution, the unit became $ per pound. This means that we did the right operation since we are looking for the price per pound.
To check if we computed for the correct value, we should multiply $1.8 to 5. If the answer from doing this is $9, then our answer is correct.
Checking:
$1.8 * 5 = $9
Therefore, the cost of 1 pound of avocado is $1.8
Step-by-step explanation: