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3 years ago

12

Create and solve a word problem that involves both Revenue and Cost. Your problem should include Break-Even and graphs of both t

he Revenue and Cost.

1 answer:

umka2103 [35]3 years ago

7 0

Answer:

HOLA BB COM O ESTAS DIME QUE TE AYUDO BB

Step-by-step explanation:

You might be interested in

Evaluate when a = 8 and b = 4. <br><br> ab^2<br> a−b

eduard

<span>Evaluate when a = 8 and b = 4.

ab^2
a−b

ab² = (8)(4)² = 8*16= 128

a - b = 8 - 4 = 4 </span>

3 0

3 years ago

The length of the sides DEF are 12,16,and 20. Find the perimeter of the triangle formed by connection the midpoints of the sides

Mekhanik [1.2K]

Answer:

24 units

Step-by-step explanation:

According to the midsegment theorem, the length of each side of the formed triangle is the half the parallel side of DEF.

<u>So the perimeter is:</u>

P = 1/2(12 + 16 + 20) = 24

6 0

2 years ago

Write a rule for the function whose graph can be obtained from the given parent function by performing the given transformations

kati45 [8]

ANSWER

$g(x) = {(x + 5)}^{3} + 4$

EXPLANATION

Given the parent function:

$f(x) = {x}^{3}$

If we shift the graph of f(x), 5 units to the left, then the new rule is

$x \to \: {(x + 5)}^{3}$

If we again, shift this graph upward by 4 units, then the completely transformed function will have the rule,

$x \to \: {(x + 5)}^{3} + 4$

Or

$g(x) = {(x + 5)}^{3} + 4$

7 0

3 years ago

If the length of a rectangle is 4 more than the width and if the perimeter of the rectangle is 52, what is the width of the rect

Ymorist [56]

Answer:

11

Step-by-step explanation:

Perimeter is figured out by adding all 4 sides.

Width of 11 + width 11 + length 15 + length 15 = 52

And the length of 15 is 4 more than the width of 11

5 0

2 years ago

Ben, Shaneeka, and Phil live on the same street. Ben lives 6/11 mile north of Phil, and 1/3 mile north of Shaneeka. How far does

Norma-Jean [14]

Answer:

Shaneeka live from Phil 7/33 mile far.

Step-by-step explanation:

Given:

Ben lives 6/11 mile north of Phil, and 1/3 mile north of Shaneeka.

Now, to get how far does Shaneeka live from Phil.

So, by subtracting the distance from 6/11 mile north where Ben lives from Phil to 1/3 mile north where Ben lives from Shaneeka:

$\frac{6}{11} -\frac{1}{3}$

$=\frac{6\times 3 -1\times 11}{33}$

$=\frac{18-11}{33}$

$=\frac{7}{33}$

Therefore, Shaneeka live from Phil 7/33 mile far.

7 0

3 years ago