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Nostrana [21]
3 years ago
12

Create and solve a word problem that involves both Revenue and Cost. Your problem should include Break-Even and graphs of both t

he Revenue and Cost.
Mathematics
1 answer:
umka2103 [35]3 years ago
7 0

Answer:

HOLA BB COM O ESTAS DIME QUE TE AYUDO BB

Step-by-step explanation:

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What is 4627926 rounded to the nearest 100000
Hunter-Best [27]

500000 that's the answer
6 0
3 years ago
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Solve the absolute value equation<br> algebraically: 3|2x - 3| + 2 = 3
kupik [55]

Answer:

3 |2x - 3|  = 1

3 |2x - 3|  = 1 \\ 6x - 9 = 1 \\ 6x = 10 \\ x =  \frac{10}{6}  = \frac{5}{3}

3 |2x - 3|  =  - 1 \\ 6x - 9 =  - 1 \\ 6x = 8 \\ x =  \frac{4}{3}

x =  \frac{5}{3} x =  \frac{4}{3}

I am sorry but I am not sure of this :(

7 0
3 years ago
Solve 8(m - 5 ) = 48
Art [367]

Answer

1)8(m -5 ) = 48 \\ 8m - 40 = 48 \\ 8m = 48 + 40 \\ 8m = 88 \\  \frac{8m}{8}  =  \frac{88}{8}  \\ m = 11

2)x + 7 = 13 \\ x = 13 - 7 \\ x = 6

3)3h - 5 = 12 \\ 3h = 12 + 5 \\ 3h = 17 \\  \frac{3h}{3}  =  \frac{17}{3}  \\ h = 5 \frac{2}{3}

Hope this helps you.

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4 0
3 years ago
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A sample of 15 commuters in Chicago showed the average of the commuting times was 33.2 minutes. If s = 8.3 minutes, find the 95%
OleMash [197]

Answer:

The 95% confidence interval of the true mean.

(29.4261 ,36.9739)

Step-by-step explanation:

<u>Step :- (i)</u>

Given sample size 'n' =15

sample of the mean x⁻ = 33.2

The standard deviation of the sample 'S' = 8.3

<u>95% of confidence intervals</u>

<u></u>(x^{-} - t_{\alpha } \frac{S}{\sqrt{n} } ,x^{-} + t_{\alpha }\frac{S}{\sqrt{n} } )<u></u>

<u>Step:-(ii)</u>

<u>The degrees of freedom γ=n-1 = 15-1=14</u>

The tabulated value t = 1.761 at 0.05 level of significance.

now substitute all possible values, we get

(33.2 - 1.761\frac{8.3}{\sqrt{15} } ,33.2+ 1.761\frac{8}{\sqrt{15} } )

After calculation , we get

(33.2-3.7739 , 33.2+3.7739

(29.4261 ,36.9739)

<u>Conclusion</u>:-

the 95% confidence interval of the true mean.

(29.4261 ,36.9739)

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Two million three hundred and twenty thousand five hundred and two as a number
dem82 [27]
2,320,502 <=== Two million, three-hundred and twenty thousand five hundred and two
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