Answer:
103 students live 1 mile away from the school.
Step-by-step explanation:
First dicide what the problem is really asking you then you end up getting divisoin them divide 515/3.
Cost per bottle
6 pack is 3.79 so the cost per bottle is 3.79/6=$0.631666666666667 per bottle
9 pack is 4.50 so the cost per bottle is 4.50/9=$0.50 per bottle
12 pack is 6.89 so the cost per bottle is 6.89/12=$0.574166666667 per bottle
0.63>0.57>0.50
the one that costs the least per bottle is the 9 pack which costs $0.50 per bottle
<u>Answer:</u>
![\boxed{\boxed{\pink{\bf \leadsto It \ will \ take \ 5 hours \ to \ travel \ 300 \ miles. }}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cboxed%7B%5Cpink%7B%5Cbf%20%5Cleadsto%20It%20%5C%20will%20%5C%20take%20%5C%205%20hours%20%5C%20to%20%5C%20travel%20%5C%20300%20%5C%20miles.%20%7D%7D%7D)
<h3>
<u>Step-by-step explanation:</u></h3>
According to Question , a plane travels 120 miles in 2 hours. So here we will use unitary method .
![\bf\implies If \ it \ covers \ 120 \ miles \ in \ 2 \ hours \\\\\bf\implies Then \ one \ mile \ will \ be \ covered \ in \ \dfrac{120}{2} hrs \\\\\bf\implies Hence \ 300 \ miles \ will \ be \ covered \ in \ \dfrac{2}{120}\times 300 hrs = \red{5 \ hours }](https://tex.z-dn.net/?f=%5Cbf%5Cimplies%20If%20%5C%20it%20%5C%20covers%20%5C%20120%20%5C%20miles%20%5C%20in%20%5C%202%20%5C%20hours%20%5C%5C%5C%5C%5Cbf%5Cimplies%20Then%20%5C%20one%20%5C%20mile%20%5C%20will%20%5C%20be%20%5C%20covered%20%5C%20in%20%5C%20%5Cdfrac%7B120%7D%7B2%7D%20hrs%20%5C%5C%5C%5C%5Cbf%5Cimplies%20Hence%20%5C%20300%20%5C%20miles%20%5C%20will%20%5C%20be%20%5C%20covered%20%5C%20in%20%5C%20%5Cdfrac%7B2%7D%7B120%7D%5Ctimes%20300%20hrs%20%3D%20%5Cred%7B5%20%5C%20hours%20%7D%20)
<h3>
<u>Hence</u><u> </u><u>it </u><u>will</u><u> </u><u>cover</u><u> </u><u>30</u><u>0</u><u> </u><u>miles</u><u> </u><u>in</u><u> </u><u>5</u><u> </u><u>hours</u><u> </u><u>.</u></h3>
Here it was a case of direct proportion in which if two things are directly proportional to each other. If one thing thing increases then the value of second also increases. Here if the time increases then the distance also increases