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Norma-Jean [14]
4 years ago
10

What is the minimum value of y =(x-1)2 (squared) +3

Mathematics
1 answer:
Delvig [45]4 years ago
4 0
The minimum is <em>X=1</em> and <em>Y=3</em>, so the minimum is <em>x=3</em>. Use a graphing calculator then Google Search, "<em>How to find the minimum of a graph using a graphing calculator.</em>". The process of this is way to long to explain here, and is best explained visually.
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A large pizza at Palanzio's Pizza starts at $6.80 with a $0.90 charge per extra topping. A large pizza a Guido's Pizza starts at
vazorg [7]

Answer:

Palanzio's Pizza: Y= .90x+6.80

Giudo's Pizza: Y= .65x+7.30

.90x + 6.80= .65x + 7.30

.25x + 6.80= 7.30

.25x = .50

x = 2

8 0
3 years ago
Ann, Jim, and Miguel sent a total of 115
FromTheMoon [43]
Ann: 21
Jim: 31
Miguel: 63



Let’s start by finding Ann’s number.

a + (a + 10) + 3a = 115

5a + 10 = 115

5a = 115 - 10

5a = 105

a = 105 / 5

a = 21

Now, just find the others’ numbers using Ann’s.

Jim sent ten more messages than Ann, and 21 + 10 = 31.

Miguel sent 3 times as many messages as Ann, and 21 * 3 = 63.
3 0
4 years ago
What is the slope of the line through (-1,2) and (-3,2)
Dafna1 [17]

Answer:

0/-2; undefined

Step-by-step explanation:

8 0
3 years ago
David has a bag of coins. The bag contains 7 dimes, 2 nickels, and 6 pennies. He will randomly select 2 coins from the bag one a
zmey [24]

Answer:

0.2

Step-by-step explanation:

\frac{7}{15} x \frac{6}{14} = 0.2

6 0
3 years ago
ITS TIMED PLEASE HELP​
Lubov Fominskaja [6]

Answer:

The graph of the function f(x)=\frac{1}{2}x^{2}-4x+5 has a minimum located at (4,-3)

Step-by-step explanation:

we know that

The equation of a vertical parabola in vertex form is equal to

f(x)=a(x-h)^{2}+k

where

a is a coefficient

(h,k) is the vertex of the parabola

If a > 0 the parabola open upward and the vertex is a minimum

If a < 0 the parabola open downward and the vertex is a maximum

In this problem

The coefficient a must be positive, because we need to find a minimum

therefore

Check the option C and the option D

Option C

we have

f(x)=\frac{1}{2}x^{2}-4x+5

Convert to vertex form

f(x)-5=\frac{1}{2}x^{2}-4x

Factor the leading coefficient

f(x)-5=\frac{1}{2}(x^{2}-8x)

f(x)-5+8=\frac{1}{2}(x^{2}-8x+16)

f(x)+3=\frac{1}{2}(x^{2}-8x+16)

f(x)+3=\frac{1}{2}(x-4)^{2}

f(x)=\frac{1}{2}(x-4)^{2}-3

The vertex is the point (4,-3) ( is a minimum)

therefore

The graph of the function f(x)=\frac{1}{2}x^{2}-4x+5 has a minimum located at (4,-3)

5 0
4 years ago
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