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3 years ago

Can an object accelerate yet neither sped up nor slow down?

1 answer:

4 0

<span>Yes, positive acceleration means to start to move more quickly. Negative acceleration means to start to move slowly. But, if an object changes direction it is also accelerating. The main reason an object is accelerating, is a change in velocity.</span>

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Assume that a machine puts out 8000 joules of work when the user puts in 10,000 joules of work. What is the efficiency of the ma

-BARSIC- [3]

Answer:

80 Percent

Explanation:

E=energy output/energy input×100

E=8000/10000×100

E=0.8×100

E=80 percent.

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6 0

3 years ago

What would happen if the compass were moved to the location of the black X

e-lub [12.9K]

Answer:

It is C

Explanation:

8 0

3 years ago

Read 2 more answers

"The drawing shows three layers of different materials, with air above and below the layers. The interfaces between the layers a

My name is Ann [436]

Answer:

Angle of incidence that entered material b= 63.1°

Angle of incidence between a and b = 55.9°

Explanation: Using the formular:

n1sintheta1= n2sintheta2

The light ray which enters material B will be

1.4Sin72.8° = 1.5Sin theta

1.3373= 1.5Sintheta

sintheta = 1.3373/1.5

Sin^-1 0.8916 = Theta

63.1 = theta

When the ray hits interface with material a

1.5Sin63.1 = 1.3 Sin theta

1.3374 = 1.3Sin theta

Sintheta= 1.3374/1.3

Sin theta = 1.0877

There will be total reflection off the boundary b c because sin theta exceeded 1 in value.

The equation should be

1.4sin63.1 = 1.4 sin theta

Sin theta=72.8°

When the ray hits air-c boundary:

1.4sin72.8=1.00sin theta

Sin theta=1.3374/1 =1.3374

There is total reflection.

In material a,the ray will:

1.3sin72.8° = 1.00sin theta

There will be total reflection when the ray hits a-b boundary.

1.3sin72.8= 1.5sintheta

Sin theta= 1.2419/ 1.5

Sin theta =0.8279

Theta= Sin^-10.8279= 55.88°

When ray hits c-air boundary

1.4sin63.1= 1.00sintheta

1.2485= sin theta = Toal reflection.

Therefore when the ray of light pass through the layers of material a, b and c the boundary with air on top and bottom will be total reflection.

7 0

4 years ago

How long will it take a 2.3"x10^3 kg truck to go from 22.2 m/s to a complete stop if acted on by a force of -1.26x10^4 N.What wo

Greeley [361]

The stopping distance is 45.0 m

Explanation:

First of all, we find the acceleration of the truck, by using Newton's second law:

$F=ma$

where

$F=-1.26\cdot 10^4 N$ is the net force on the truck

$m=2.3\cdot 10^3 kg$ is the mass of the truck

a is its acceleration

Solving for a,

$a=\frac{F}{m}=\frac{-1.26\cdot 10^4}{2.3\cdot 10^3}=-5.48 m/s^2$

where the negative sign means the acceleration is opposite to the direction of motion.

Now, since the motion of the truck is at constant acceleration, we can apply the following suvat equation:

$v^2-u^2=2as$

where

v = 0 is the final velocity of the truck

u = 22.2 m/s is the initial velocity

$a=-5.48 m/s^2$ is the acceleration

s is the stopping distance

And solving for s,

$s=\frac{v^2-u^2}{2a}=\frac{0-(22.2)^2}{2(-5.48)}=45.0 m$

Learn more about accelerated motion:

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6 0

4 years ago

Compare and contrast transverse and longitudinal waves

Nataliya [291]

In both transverse and longitudinal waves; energy is transferred in form of a wave.

The difference between transverse and longitudinal waves is that:

In transverse waves; the displacement of the medium is perpendicular to the propagation of the waves.

In longitudinal waves; the displacement of the medium is parallel to the propagation of the waves.

5 0

3 years ago

Read 2 more answers