Answer:
The coefficient of friction is 0.34
Explanation:
It is given that,
Mass of the load, m = 1000 kg
It is dragged up an incline at 10 degrees to the horizontal by a force of 5 KN applied in the most effective direction, F = 5 × 10³ N
We need to find the coefficient of friction between the surface and the load. From the attached figure, the load is dragged up with a force of F. A frictional force f will also act in this scenario.
So, 
Since, 
or 
So, the coefficient of friction is 0.34. Hence, this is the required solution.
First we assume there is no fiction, this is just a basic assumption of all physics problems. We also assume the rope is massless and does not change length since this problem is significantly more complicated if the rope has a mass or can change length.
For part (a) it asks about a system in equilibrium so we see that m1 is hanging vertically and if the system is in equilibrium then all the forces are constant. So I m1 is 7.0 kg then the force of gravity is
Fg = (7.0 kg) (10 N/kg) = 70 N
Since the forces are balanced there must be 70 N pulling it up. All that force is done by the other mass and transfered through the massless rope.
In this case the force of gravity on m2 is 336.681N (see the attached picture for explanation).
So if the force on m2 is about 337 N then it's mass is
m = (337 N) / (10 N/kg) = 33.7 kg
For part (b) it asks about a system where there are unbalanced forces. If m2 slides down with any acceleration and the rope cannot change length then m1 must be accelerating at the same rate. So if m1 accelerates at .4 m/s^2 then the force is
F = Fg + Fm2
F = 70 N + (7.0 kg) (.4m/s^2) = 70 N + 2.8 N = 72.8 N
So now the process for finding the mass of the other block is the same except instead of using 70 in the equation you use 72.8 N. So the new force is 350.149. So the mass must be equal to
m = (350) / (10 N/kg) = 35 kg
Answer:
The distance traveled by the car is 60 miles and the displacement of the car is 20 miles in the north direction.
Explanation:
The distance is the total length of the car's path.
d = 40 mi + 20 mi
d = 60 mi
The displacement is the distance between the starting position and the final position.
x = (40 − 20) mi N
x = 20 mi N
Answer:
direction does the axis of rotation tilt toward after the blow is the z- direction
Explanation:
This is because
Due to the blow, there is a impulse imparted on the ball which gives a change in linear momentum () in the x direction
Thus When cross product of momentum in x direction is taking with r vector, we will get resultant in z direction. Hence change in angular momentum will be z direction.
Answer:
ummm there is nothing attached :(
Explanation:
