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sveta [45]
2 years ago
5

A weightlifter raises a 180-kg barbell to a height of 1.95 m. How much work is done by the weightlifter in lifting the barbells

Physics
1 answer:
melamori03 [73]2 years ago
8 0

P= 10m = 10 x 180 = 1800 N

work is done by the weightlifter in lifting the barbells :

A= Ph = 1800 x 1.95 = 3510 J

ok done. Thank to me :>

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In a simple circuit a 6-volt dry cell pushes charge through a single lamp which has a resistance of 3 Ω. According to Ohms law t
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<em>In a simple circuit a 6-volt dry cell pushes charge through a single lamp which has a resistance of 3 Ω. According to Ohms law the current through the circuit is _____________ Amps. </em>

According to Ohm’s law V =I*R  

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<em> If a second identical lamp is connected in series, the 6-volt battery must push a charge through a total resistance of ________ Ω</em>.  <em>The current in the circuit is then __________ Amps. </em>

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2 resistance in series  R₂ =  6Ω

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The current is 1 Amps

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<em>If a third identical lamp is connected in series, the total resistance is now _________Ω.  The current through all three lamps in series is now _________ Amps.  </em>

Since the third lamp is connected in series with the first and second, the total resistance will R₃ = 3 + 3 + 3 = 9Ω

total resistance of the 3 lamps R₃ =  9Ω

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I =V/R₃ =6/9 = 0.67 Amps

The current through the 3 lamps I₃ = 0.67 Amps

Answer =  9Ω  and 0.67 Amps

<em>The current through each individual lamp is __________ Amps.  </em>

Since all 3 lamps are connected in series, the same current will flow through each of the  3 lamps, and that current is I₃  

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<em>What is the power when a voltage of 120 volts drives a current of 3 amps through a device?  </em>

The formula for power P = I*V =120*3 = 360 Watts

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<em>What is the current when a 90-W light bulb is connected to 120 V? </em>

From P =I*V, make I the subject of the formula, I = P/V =90/120 = 0.75

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<em>How much current does a 75-W light bulb draw when connected to 120 V?</em>  

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<em>If part of an electric circuit dissipates energy at 6 W when it draws a current of 3 A, what voltage is impressed across it? </em>

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The power rating of the bulb is 60W = 60/1000 = 0.06 KiloWatt

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Answer =  $4.32

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