Answer:
9 and 8, 12 and 6, 18 and 4, 24 and 3, 36 and 2
Step-by-step explanation:
.-.
0=0, all numbers are solutions
Answer:
The answer is a =3/4 and 5/18
Step-by-step explanation:
Answer:
The value of the side PS is 26 approx.
Step-by-step explanation:
In this question we have two right triangles. Triangle PQR and Triangle PQS.
Where S is some point on the line segment QR.
Given:
PR = 20
SR = 11
QS = 5
We know that QR = QS + SR
QR = 11 + 5
QR = 16
Now triangle PQR has one unknown side PQ which in its base.
Finding PQ:
Using Pythagoras theorem for the right angled triangle PQR.
PR² = PQ² + QR²
PQ = √(PR² - QR²)
PQ = √(20²+16²)
PQ = √656
PQ = 4√41
Now for right angled triangle PQS, PS is unknown which is actually the hypotenuse of the right angled triangle.
Finding PS:
Using Pythagoras theorem, we have:
PS² = PQ² + QS²
PS² = 656 + 25
PS² = 681
PS = 26.09
PS = 26
0.04 Times .100 is 0.004. You’re just moving the 4 over a place value (from hundredths place to thousandths place). Notice that if you did 0.04 times 100 you would get 4. Essentially you’re just moving the 4 to different places and adding zeros.
