First answer is 135 and Second answer is 900
Red Perimeter= 4u X π= 4uπ
Blue Perimeter= u X π= uπ
Red Area= 2u X 2u X π= 4u2π
Blue Area= u X u X π= u2π
For line B to AC: y - 6 = (1/3)(x - 4); y - 6 = (x/3) - (4/3); 3y - 18 = x - 4, so 3y - x = 14
For line A to BC: y - 6 = (-1)(x - 0); y - 6 = -x, so y + x = 6
Since these lines intersect at one point (the orthocenter), we can use simultaneous equations to solve for x and/or y:
(3y - x = 14) + (y + x = 6) => 4y = 20, y = +5; Substitute this into y + x = 6: 5 + x = 6, x = +1
<span>So the orthocenter is at coordinates (1,5), and the slopes of all three orthocenter lines are above.</span>
Answer:
Height of cylinder (h) = (4/3)R
Step-by-step explanation:
Given:
Radius of cylinder (r1) = R
Height of cylinder (h) = H
Radius of sphere (r2) = R
Volume of cylinder = volume of sphere
Find:
Height of cylinder (h) = H = ?
Computation:
Height of cylinder (h) = (4/3)R
-54 i think is the answer
