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Alexeev081 [22]

3 years ago

14

A population of 422,000 increases by 12% each year. What is the approximate population after 5 years?

1 answer:

Zarrin [17]3 years ago

4 0

Here are formulas we choose from
Increasing: y = a (1 + r)x Decreasing: y = a(1 - r)x

we want increasing

422000(1+.12)^5
743,708 (you don't want the decimals because you can't divide a human...)

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The probability, P, that a person responds to an advertisement can be modeled by the exponential function P = 1 – e^-0.047t. In

MA_775_DIABLO [31]

To solve this equation, start by noticing that you want to find t when P is 75%, or 0.75. Plug in 0.75 for P. Please see the attached screenshot for a step-by-step. The correct answer is 29.496 days.

EDIT 2: I actually was correct! You check the answer by substituting 29.496 for t in the original equation set equal to 0.75. It is 0.75. I had forgotten the negative sign when I checked.

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3 years ago

The vertex from of the equation of a parabola is y = (x - 3)2 + 36 what is tge standard form of the equation

Misha Larkins [42]

Multiply it out and collect terms.
y = (x - 3)² + 36
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3 years ago

Jenna is having a sidewalk sale. She pays $12 for a

RSB [31]

Answer:

25.5

Step-by-step explanation:

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4 0

3 years ago

a sprinter increases the speed from 0 meters per second to 9 meters per second in 2 seconds. what is the acceleration

mote1985 [20]

Answer:

The acceleration is

$4.5 {ms}^{ - 2}$

Step-by-step explanation:

Use the equation of motion,

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We substitute the values into the equation and solve for the acceleration, a

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This means that;

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3 years ago

CALCULUS: Determine which function is a solution to the differential equation y ' − y = 0.

Montano1993 [528]

C: none of these are solutions to the given equation.

• If<em> y(x)</em> = <em>e</em>², then <em>y</em> is constant and <em>y'</em> = 0. Then <em>y'</em> - <em>y</em> = -<em>e</em>² ≠ 0.

• If <em>y(x)</em> = <em>x</em>, then <em>y'</em> = 1, but <em>y'</em> - <em>y</em> = 1 - <em>x</em> ≠ 0.

The actual solution is easy to find, since this equation is separable.

<em>y'</em> - <em>y</em> = 0

d<em>y</em>/d<em>x</em> = <em>y</em>

d<em>y</em>/<em>y</em> = d<em>x</em>

∫ d<em>y</em>/<em>y</em> = ∫ d<em>x</em>

ln|<em>y</em>| = <em>x</em> + <em>C</em>

<em>y</em> = exp(<em>x</em> + <em>C </em>)

<em>y</em> = <em>C</em> exp(<em>x</em>) = <em>C</em> <em>eˣ</em>

8 0

3 years ago