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skelet666 [1.2K]
3 years ago
15

Plz help me I'm from k12

Mathematics
2 answers:
viva [34]3 years ago
4 0
It would be 9.4 minus 1.8. i go their to!
Aleksandr [31]3 years ago
3 0
I would choose a for your answerr
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Mr.Williams drew
tia_tia [17]

Answer: Answer C , Only student 2, because dilation preserve angle measures and side lengths are proportional

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3 years ago
Yoshi and Rana serve muffins. There are 3 muffins with nuts. 1/6 of the muffins have nuts. How many muffins do they serve in all
Solnce55 [7]
Total amount of muffins: 3×6= 18 muffins.

Amount of muffins without nuts:
total amount of muffins - muffins with nuts
18-3= 15 muffins without nuts

6 0
3 years ago
Read 2 more answers
Which of the following are perfect squares? 2, 4, 6, 16, 20,25, x², x³, x¹⁵, x²⁰, x²⁵
coldgirl [10]

Answer:

4, 16, 25, x^{2}, x^{20}\\.

Step-by-step explanation:

4 0
2 years ago
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PQ⊥PS , m∠QPR=7x−9, m∠RPS=4x+22<br> Find : m∠QPR
emmainna [20.7K]

Given:

It is given that,

PQ ⊥ PS and

∠QPR = 7x-9

∠RPS = 4x+22

To find the value of ∠QPR.

Formula

As per the given problem PR lies between PQ and PS,

So,

∠QPR+∠RPS = 90°

Now,

Putting the values of ∠RPS and ∠QPR we get,

7x-9+4x+22 = 90

or, 11x = 90-22+9

or, 11x = 77

or, x = \frac{77}{11}

or, x = 7

Substituting the value of x = 7 in ∠QPR we get,

∠QPR = 7(7)-9

or, ∠QPR = 40^\circ

Hence,

The value of ∠QPR is 40°.

3 0
3 years ago
Do you think the equations (x−1)(x+3)=17+x and (x−1)(x+3)+500=517+x should have the same solution set? Why?
oksano4ka [1.4K]

Answer:

Those two pair of equations have the same solution set.

Step-by-step explanation:

There are two equations  

(x-1)(x+3)=17+x ..... (1) and  

(x-1)(x+3)+500=517+x ...... (2)

We have to check the same solution set will be there for equations (1) and (2) or not.

Now, we are going to rearrange the equation (2).

(x-1)(x+3)+500=517+x

⇒ (x-1)(x+3)=517-500+x

⇒(x-1)(x+3)=17+x

This is the same equation as equation (1).  

Therefore, there will be the same solution set for equations (1) and (2).  (Answer)

There are two equations  

(x-1)(x+3)=17+x ..... (3) and  

3(x-1)(x+3)+500=51+3x ...... (4)

We have to check the same solution set will be there for equations (3) and (4) or not.

Now, we are going to rearrange the equation (4).

3(x-1)(x+3)+500=51+3x

⇒ 3(x-1)(x+3)=3(17+x)

⇒(x-1)(x+3)=17+x

This is the same equation as equation (3).  

Therefore, there will be the same solution set for equations (3) and (4). (Answer)

7 0
3 years ago
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