-63/50
I think this is what you mean by simplest fom
Answer:
The minimum score required for recruitment is 668.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

Top 4%
A university plans to recruit students whose scores are in the top 4%. What is the minimum score required for recruitment?
Value of X when Z has a pvalue of 1-0.04 = 0.96. So it is X when Z = 1.75.




Rounded to the nearest whole number, 668
The minimum score required for recruitment is 668.
Answer:
t =5
Step-by-step explanation:
-7(2-t)=21
-14+7t=21
7t=35
t=5
Answer:
length TR = 6
Step-by-step explanation:
Length TL = 24
scale ratio = 3:4:5
T-------R--------V----------L
find: TR
24 / (3+4+5) = 2
length TR at 3 x 2 = 6
length RV at 4 x 2 = 8
length VL at 5 x 2 = 10
a total of 6 + 8 + 10 = 24
therefore,
length TR = 6
Answer:
-8y+12
Step-by-step explanation:
4(-2y +3)
you can distribute the 4
4 • -2y + 4 • 3
= -8y +12
because they are not like terms, you cannot do anything further.