Solve your equation step-by-step.
x2+4x+4=0
Factor left side of equation.
(x+2)(x+2)=0
Set factors equal to 0.
x+2=0
or
x+2=0
x=−2
Answer:
5
Step-by-step explanation:
answer my last question plz
7 is the lowest common multiple i think
Answer:
45°
Step-by-step explanation:
Let's understand "supplement" and "complement" -- basics of geometry of angles.
- When we say two angles, a & b, are supplementary, we mean that both ADD up to 180.
- When we say two angles, a & b, are complementary, we mean that both ADD up to 90.
<em><u>If we have given an angle, such as "x", to find its supplement, we subtract the angle from 180. Similarly, we would need to subtract the angle x from 90 if we were to find the complement of the angle.</u></em>
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We want to find complement of 45, so we subtract 45 from 90 to get:
90 - 45 = 45°
Hence, the complement of a 45° angle = 45°
Answer: The square root of π has attracted attention for almost as long as π itself. When you’re an ancient Greek mathematician studying circles and squares and playing with straightedges and compasses, it’s natural to try to find a circle and a square that have the same area. If you start with the circle and try to find the square, that’s called squaring the circle. If your circle has radius r=1, then its area is πr2 = π, so a square with side-length s has the same area as your circle if s2 = π, that is, if s = sqrt(π). It’s well-known that squaring the circle is impossible in the sense that, if you use the classic Greek tools in the classic Greek manner, you can’t construct a square whose side-length is sqrt(π) (even though you can approximate it as closely as you like); see David Richeson’s new book listed in the References for lots more details about this. But what’s less well-known is that there are (at least!) two other places in mathematics where the square root of π crops up: an infinite product that on its surface makes no sense, and a calculus problem that you can use a surface to solve.
Step-by-step explanation: this is the same paragraph The square root of π has attracted attention for almost as long as π itself. When you’re an ancient Greek mathematician studying circles and squares and playing with straightedges and compasses, it’s natural to try to find a circle and a square that have the same area. If you start with the circle and try to find the square, that’s called squaring the circle. If your circle has radius r=1, then its area is πr2 = π, so a square with side-length s has the same area as your circle if s2 = π, that is, if s = sqrt(π). It’s well-known that squaring the circle is impossible in the sense that, if you use the classic Greek tools in the classic Greek manner, you can’t construct a square whose side-length is sqrt(π) (even though you can approximate it as closely as you like); see David Richeson’s new book listed in the References for lots more details about this. But what’s less well-known is that there are (at least!) two other places in mathematics where the square root of π crops up: an infinite product that on its surface makes no sense, and a calculus problem that you can use a surface to solve.
